Answer:
If you just solve normally, you will get x=2 and x=-3. But if you plug these in to check your work, you will find that they are wrong. Your answer is no solution
Step-by-step explanation:
ln(2x+3)+ln(x-2)=ln(x^2-2x)
<em>Rule: log(a) + log(b) = log(a*b)</em>
ln( (2x+3)(x-2) ) = ln(x^2-2x)
<em>Rule: If log(a) = log(b) then a = b</em>
(2x+3)(x-2) = x^2 - 2x
2x^2-x-6=x^2-2x
x^2+x-6=0
<em>Using Quadratic Formula:</em>
x = 2 and x = -3
But, plugging these numbers back into the original equation is false!
Answer:
b 41cm, 40cm, 9cm form a right angle
(w15w5)4m is the same as
4m(15w•5w)
This is because w•15 is still 15w and w•5 is still 5w, it’s just a way of organizing it!!! And it doesn’t matter if the 4m is behind or in front of the (w15w5) because you still distribute normally!
Now let’s distribute!
But wait, there has to be order of operations here !!!
PEMDAS
So let’s do 15w•5w which equals 75w^2 since 15•5 is 75 and when you are multiplying two variables together you get the variable, squared because w•w=w^2
Think of it as 2•2=4 which is 2^2!!!
So then we are left with 4m•75w^2 which is
300mw^2 this is because when you are multiplying two unknown variables you have to make them join together, so first let’s multiply the coefficients(the real numbers)!
75•4=300
then m•w^2 which is just mw^2!!
So the final answer is 300mw^2!!
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