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alexdok [17]
2 years ago
8

1. Use the distributive property to simplify. -7( y + 9) - (y + 4) I

Mathematics
1 answer:
Oduvanchick [21]2 years ago
4 0

Answer:

-8y-67

Step-by-step explanation:

-7(y+9)-(y+4) distribute

-7y-63-y-4 combine like terms

-8y-67

i believe this is the right answer :D

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Please help with this question PLEASE!
yuradex [85]

Answer:

48 cm²

Step-by-step explanation:

The copper part is two equal triangles, find a triangle's area by counting squares and multiply by two.

Total copper=(Triangle area)(2)

=b(h)(½)(2)

=b(h)

=(6)(8)

=48 cm²

6 0
3 years ago
1/3 of 90 = 2/3 of ?
rewona [7]
Answer=45
1/3 of 90= 30
5 0
3 years ago
If the width and length of a rectangle are both increased by 10%, by what percent does the area of the rectangle increase?
S_A_V [24]

Answer:

10%

Step-by-step explanation:

We know Perimeter of rectangle

= 2 (Length + Width)

If width and length are increased by 10%

New length= L + 10/100L = (1.1) L

New width = W + 10/100W = (1.1) W

Perimeter = 2 [(1.1) L + (1.1) W]

Perimeter = 2 (1.1) (L + W)

Perimeter = (2.2) (L + W)

Increase in perimeter = 2.2 (L + W) - 2 (L + W)

The increase in Perimeter = 0.2 (L + W)

Percent increase

= 0.2 (L + W)/2 (L + W) × 100

= 0.2/2 × 100

= 0.1 × 100

= 10%

I hope this helped and if it did, please mark as Brainliest.

7 0
2 years ago
Someone help.me find angle C and D<br>also this is in CIRCLE THEOREM lesson​
Artyom0805 [142]

Step-by-step explanation:

Opposite angles in a cyclic quadrilateral are supplementary.

Therefore 3c = 4d = 180°, c = 60° and d = 45°.

8 0
2 years ago
Read 2 more answers
Find the roots of the equation<br> x ^ 2 + 3x-8 ^ -14 = 0 with three precision digits
scoray [572]

Answer:

Step-by-step explanation:

Given quadratic equation:

x^{2} + 3x - 8^{- 14} = 0

The solution of the given quadratic eqn is given by using Sri Dharacharya formula:

x_{1, 1'} = \frac{- b \pm \sqrt{b^{2} - 4ac}}{2a}

The above solution is for the quadratic equation of the form:

ax^{2} + bx + c = 0  

x_{1, 1'} = \frac{- b \pm \sqrt{b^{2} - 4ac}}{2a}

From the given eqn

a = 1

b = 3

c = - 8^{- 14}

Now, using the above values in the formula mentioned above:

x_{1, 1'} = \frac{- 3 \pm \sqrt{3^{2} - 4(1)(- 8^{- 14})}}{2(1)}

x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(1)(- 8^{- 14})})

x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(1)(- 8^{- 14})} - 3)

Now, Rationalizing the above eqn:

x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(- 8^{- 14})} - 3)\times (\frac{\sqrt{9 - 4(- 8^{- 14})} + 3}{\sqrt{9 - 4(- 8^{- 14})} + 3}

x_{1, 1'} = \frac{1}{2}.\frac{(\pm {9 - 4(- 8^{- 14})^{2}} - 3^{2})}{\sqrt{9 - 4(- 8^{- 14})} + 3}

Solving the above eqn:

x_{1, 1'} = \frac{2\times 8^{- 14}}{\sqrt{9 + 4\times 8^{-14}} + 3}

Solving with the help of caculator:

x_{1, 1'} = \frac{2\times 2.27\times 10^{- 14}}{\sqrt{9 + 42.27\times 10^{- 14}} + 3}

The precise value upto three decimal places comes out to be:

x_{1, 1'} = 0.758\times 10^{- 14}

5 0
3 years ago
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