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olga nikolaevna [1]
4 years ago
5

Elena and her husband Marc both drive to work. Elena's car has a current mileage (total distance driven) of 15,000 and she drive

s 15,000 miles more each year. Marc's car has a current mileage of 24,000 and he drives 11,000 miles more each year. Will the mileages for the two cars ever be equal? Explain
Mathematics
1 answer:
Jet001 [13]4 years ago
4 0

Let us set up a system of functions to describe the given situation and see if they ever intersect.

Elena has initially 15000 miles and adds 15000 per year.

we can describe it as Elena = 15000+15000(years).

Marc's equation can be given as = 24000+11000(years).

Setting both conditions equal, we get

15000+15000(years)=24000+11000(years).

Clubbing years on one side we get,

4000(years)=9000

Lets divide by 4000 on each side we get years = 2.25

Hence yes, the mileages will equal the same value (whatever it may be) in 2.25 years from the the beginning of the problem.


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yaroslaw [1]

Answer:

G=\frac{v^2r}{2M}

Step-by-step explanation:

v^2=\frac{2GM}{r}

\Leftrightarrow 2GM=v^2r

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Marina86 [1]

Answer:

\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2})

And when we apply the limit we got that:

\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2}) =1

Step-by-step explanation:

Assuming this complete problem: "The following formula for the sum of the cubes of the first n integers is proved in Appendix E. Use it to evaluate the limit . 1^3+2^3+3^3+...+n^3=[n(n+1)/2]^2"

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We can express this formula like this:

\lim_{n\to\infty} \sum_{n=1}^{\infty}i^3 =\lim_{n\to\infty} [\frac{n(n+1)}{2}]^2

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\lim_{n\to\infty} [\frac{n(n+1)}{2}]^2

If we operate and we take out the 1/4 as a factor we got this:

\lim_{n\to\infty} \frac{n^2(n+1)^2}{n^4}

We can cancel n^2 and we got

\lim_{n\to\infty} \frac{(n+1)^2}{n^2}

We can reorder the terms like this:

\lim_{n\to\infty} (\frac{n+1}{n})^2

We can do some algebra and we got:

\lim_{n\to\infty} (1+\frac{1}{n})^2

We can solve the square and we got:

\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2})

And when we apply the limit we got that:

\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2}) =1

3 0
3 years ago
Please help with this!
dimaraw [331]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
What is the value of t
olchik [2.2K]

Answer:

t = 89°

Step-by-step explanation:

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summing them:

(t-46)+(t)+(180-(t+43)) = 180°

t -46 + t + 180 -t -43 = 180°

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Answer: slope (m) = -2

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put it into y=mx+b

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first, parantheses.

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your new equation is y-3 = -2x-10

now, to get y by itself, cancel out the -3 by adding a positive 3 to both sides.

you final equation will be y=-2x-7

in the form y=mx+b, m is your slope.

therefore, -2 is your answer, or slope.

8 0
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