so since only 3 out of 11 went to visit then it is simple
since just 3 went and there were 11
3/11 of the students went
Well, 2/4 is equivalent to 4/8. So you can turn the 2/4 into 4/8 and then add 4/8 plus 3/8.
Let
C-------> the length of a circumference
C=2*pi*r-----> equation 1
we know that
in this problem-----> <span>the circumference of the foundation is 4 times the radius, increased by 114 ft
</span>so
C=4*r+114------> equation 2
(1)=(2)
2*pi*r=4*r+114------> 2*pi*r-4*r=114-----> r*[2*pi-4]=114---> r=114/[2*pi-4]
r=114/[2*pi-4]-----> 50 ft
the answer is
r=50 ft
If complex coefficients are allowed, the answer is 3.
If the polynomial must have real coefficients, then each complex root comes as a pair of complex conjugate roots.
Root -5 is real, so that is 1 root, and degree 1.
Root 1 + 4i is complex, so it must come with its complex conjugate, 1 - 4i. This adds 2 roots to the polynomial, and now we're up to degree 3.
Root -4i is also complex. It also must come with its complex conjugate, 4i. That adds two more roots, and the degree is 5.
Answer: The least possible degree is 5 with real coefficients.
