Points:
Quadrant I: (+, +)
Quadrant II: (-, +)
Quadrant III: (-, -)
Quadrant IV: (+, -)
Thus the point (5,4) is found in Quadrant I.
Answer:
Please refer to the attachment
(b)(b)=25 cm2
b2=25 cm2
√(b2)=√(25 cm2)
b= 5 cm
Please note the square root of 25 was taken, as well as the square root of cm2.
Perimeter=4b
Perimeter=4(5 cm)
Perimeter=20 cm
Step:
A circle of radius = 12.5 or diameter = 25 or circumference = 78.54 cm has an area of: 4.909 × 10-8 square kilometers (km²) 0.04909 square meters (m²)
Answer:
A and B
Step-by-step explanation:
9x+9+5x-6
14x+3
32x+8-18x-5
14x+3
