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2 years ago

1) Which equation has a slope m=−38

1 answer:

3 0

These are the answers I got for these questions. B, B, A, A, B, B, B, A, D, and D. I suspect that most of those questions are missing division signs. These answers should be correct.

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A 60 by 80-foot rectangular walk in a park surrounds a flower bed. If the walk is of uniform width and its area is equal to the

alekssr [168]

Answer: 17.14 ft

<u>Step-by-step explanation:</u>

The area of the flower bed is 60 ft x 80 ft = 4800 ft²

The perimeter of the sidewalk that surrounds the flower bed is:

2(60 ft) + 2(80 ft)
= 120 ft + 160 ft
= 280 ft

The area of the sidewalk is:

perimeter x width
= 280w

area of sidewalk = area of flower bed

280w = 4800

$\text{w}=\dfrac{4800}{280}$

$=\dfrac{120}{7}$

≈ 17.14

8 0

2 years ago

Find the solution of the system of equations.

Alex17521 [72]

Answer:

the answer is Solve for the first variable in one of the equations, then substitute the result into the other equation.

Point Form:

(−17/2, -7)

Equation Form:x=-17/2 y=-7

5 0

2 years ago

Read 2 more answers

Tell whether each statement is always (A), sometimes (S), or never (N) true.

AnnZ [28]

N an acute angle is 90 degrees or less and 90 + 90 is 180 and an obtuse angle is always more than 90 and always less than 180

7 0

3 years ago

{(-4,8),(-2,4),(0,1),(2,4),(4,8)}

astraxan [27]

Answer:

Since there is one value of y for every value of x in (−4,8),(−2,4),(0,1),(2,4), ( 4,8), this relation is a function. The relation is a function.

5 0

2 years ago

the density of a certain material is such that weighs 6900 grams for every 4.5 quarts of volume express this density in pounds p

dlinn [17]

Answer:

$d=101.4\ \text{pounds}/\text{feet}^3$

Step-by-step explanation:

Given that,

Mass of material, m = 6900 grams

Volume of the material, V = 4.5 quarts

We need to find the density in pounds per cubic foot

We know that,

1 pound = 453.59 grams

⇒ 6900 grams = 15.21 pounds

Also, 1 cubic foot = 29.92 quarts

4.5 quart = 0.15 feet³

Density = mass/volume

$d=\dfrac{15.21\ \text{pounds}}{0.15\ \text{feet}^3}\\\\d=101.4\ \text{pounds}/\text{feet}^3$

Hence, the density of the material is $101.4\ \text{pounds}/\text{feet}^3$

3 0

3 years ago