Here is how to solve it.
65% of 160
65/100(160)
=(65/100)(160/1)
=(13/20)(160/1)
=(13)(160)/(20)(1)
=2080/20
=104
Therefore they won 104 games! :D
Answer:
The 95% confidence interval for the proportion of young adults with pierced tongues who have receding gums is (0.24, 0.506).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 95% confidence interval for the proportion of young adults with pierced tongues who have receding gums is (0.24, 0.506).
The answer is 74.90.
I don't understand what you mean by 'Why it doesn't show'
Using difference of squares
=(a-b)(a+b)
with a = x and b = 3
i
+ 18 =(x-3
i)(x+3
i)
Answer:
38,4000 and 25,150
Step-by-step explanation:
add colum 1 and 3 together on each side for each different car and divide them by the percentage