Est Answer: say the numbers are x and y......and y being the bigger number ... If the ratio is 5:3, then difference between ratio = 5-3 = 2 ... Substituting this x = 5y/3 in equation x-y=18 we get ... therefore x = 5 * 27/3 = 5*9 = 45 .... One number is 5 more than another. their sum is 53 what are the two numbers?

5 0

3 years ago

65% of 150 estimate percent

Ksju [112]

Answer:

97.5

Brainliest answer pls

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

A cleaning company charges a fixed amount for a house call and a second amount for each room it cleans. The total cost to clean

yanalaym [24]

Answer:

$110

Step-by-step explanation:

Let the fixed amount charged be f and the amount charged to clean a room be r.

To clean six rooms , the company would charge the following, the fixed amount for the call plus the amount charged per room multiplied by 6 which of course is 6r.

Writing this in equation form,

f + 6r = 250

In likewise manner, same applies for 8 rooms.

this gives f + 8r = 320

We now have 2 equations that we will need to solve simultaneously

f + 6r = 250........(i)

f + 8r = 320........(ii)

We subtract equation ii from I to yield

2r = 70, hence r = 70/2 = 35.

We now substitute this in equation 1

f + 6(35) = 250

f + 210 = 250

f = 250 - 210 = 40

Hence, we now know that the amount charged per call is $40 while the amount charged to clean a room is $35.

We now calculate the amount charged by the company to clean 2 rooms.

This is mathematically = f + 2r

40 + 2(35) = $110.

6 0

3 years ago

Soon after taking an aspirin, a patient has absorbed 320 mg of the drug. after 3 hours, only 40 mg remain. find an exponential m

Anastaziya [24]

The equation will be of the form:
$A(t)= A_{0} e^{rt}$
where A is the amount after t hours, and r is the decay constant.
To find the value of r, we plug the given values into the equation, giving:
$40=320e^{3r}$
Rearranging and taking natural logs of both sides, we get:
$ln\ 0.125=3r$
$r=\frac{ln\ 0.125}{3}=-0.693$
The required model is:
$A=A _{0} e^{-0.693t}$

3 0

3 years ago