-5m+(-8n) simplest form

Alan, Bill, and Calvin are playing a game with collectible cards. At the moment, Alan has 11 less than 2.5 times the number of c

oksian1 [2.3K]

Answer:

50

Step-by-step explanation:

I'm sorry but your missing the questions but I found a close answer! Let A be the number of cards Alan has B be the number of cards Bill has C be the number of cards Calvin has Alan had 11 less than 2 1/2 times the number of cards bill has. is 2.5 Alan is 2.5 of bill has minus 11 A=2.5B -11 Calvin has 1 more than 1 1/2 times the number of cards bill has. is 1.5 Calvin is 1.5 of bill has plus 1 C=1.5B + 1 Alan and Calvin have the same number of cards So A=C WE plug in A and C equations and solve for B 2.5B -11 = 1.5B + 1 (subtract 1.5B on both sides) 1B -11 = 1 (Add 11 on both sides) B = 12 If Alan and Calvin have the same number of cards, the number bill has is 12 The number of cards Alan and Calvin each have is 19 Total cards = 12 + 19 + 19 = 50 If Alan, bill, and Calvin have all the cards in the deck then the deck has 50 cards.

3 0

2 years ago

Find the Expression OF this equation. c/3 / ac/4 QUESTION C

Fiesta28 [93]

Answer:

See below

Step-by-step explanation:

$(a) \: \: x = \frac{c}{3} \\ \\ \implies \: {x}^{2} = { \bigg( \frac{c}{3} \bigg) }^{2} \\ \\ \bold{\implies \: {x}^{2} = \frac{ {c}^{2} }{9} } \\ \\ (b) \: \: x + y = \frac{c}{3} + \frac{ac}{4} \\ \\\implies \: \bold{x + y = \frac{4c + 3ac}{12} } \\ \\ \frac{xy}{z} = \frac{ \frac{c}{3} \times \frac{ac}{4} }{ \frac{ {a}^{2} }{2c + 1} } \\ \\ = \frac{ \frac{ac ^{2} }{12} }{ \frac{ {a}^{2} }{2c + 1} } \\ \\ = \frac{a {c}^{2} }{12} \times \frac{2c + 1}{ {a}^{2} } \\ \\ \implies\bold{\frac{xy}{z} = \frac{ {c}^{2}(2c + 1) }{12a} }$

8 0

2 years ago

Johns collection contains US, Indian and British stamos. If the stamps ratios of US to Indian stamps is 5 to 2, and the ratio of

NARA [144]

Figure out what is the commonality for each ratio.
There are India stamps in each ratio, so India is the commonality.

Now you simply take the two ratios and multiply them until India has the same amount.

So, Multiply the first by 5 to get a ratio of 25 US to 10 Indian
Multiply the second by 2 to get a ratio of 10 Indian to 2 British

Now that you have "10 Indian" in both ratios, they match up
You have 25 US : 10 Indian : 2 British.

Since the answer is only asking for US and British, you only need 25 US : 2 British

8 0

3 years ago

If there are 1500 guests, only 1 of them brought a coupon for free admission to the carnival?

wlad13 [49]

So 1/50 brought the pass
x out 1500
1/50 = x/1500
cross multiply
1500 = 50x
divide both sides by 50
30 = x

You can expect for 30 out of the 1,500 to receive free admissions.

Hope this helps

4 0

3 years ago

Students reported practicing violin during the last semester for 45, 38, 52, 58, and 42 hours. What is the mean absolute deviati

borishaifa [10]

6.4 is the answer you are looking for! Hope that helps :))

6 0

3 years ago