1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anvisha [2.4K]
3 years ago
9

There were 5 1/3 jars of pickles.Ann and her friend ate 1 1/3 jar. How many jars of pickles are left?

Mathematics
2 answers:
Anarel [89]3 years ago
5 0
5 1/3-1 1/3=4 u have the same denominators so u can subtract
Dennis_Churaev [7]3 years ago
3 0
4 take away the 1/3 so there is no fraction and 5 - 1 equals 4
You might be interested in
Multiplication of fractions<br>3/4×7/15​
Pachacha [2.7K]

Answer:

\frac{7}{20} or <em>0.35</em>

Step-by-step explanation:

\frac{3}{4} * \frac{7}{20} \\3*7=21\\4*15=60\\\frac{21}{60} \\

Now simplify.

\frac{21}{60} = \frac{7}{20}

3 0
2 years ago
If P is the incenter of triangle JKL, find the measure of JKP.
ladessa [460]

Answer:

m∠JKP = 31.5°

Step-by-step explanation:

Incenter of a triangle is the point where all the bisectors of interior angles intersect each other.

JN is the angle bisector of ∠KJL.

Therefore, m∠KJN = m∠LJN

(7x - 6) = (5x + 4)

7x - 5x = 6 + 4

2x = 10

x = 5

m∠KJN = (7x - 6)

            = 7(5) - 6

            = 35 - 6

            = 29°

In ΔKJN,

m∠JKN + m∠KNJ + m∠NJK = 180°

m∠JKN + 90° + 29° = 180°

m∠JKN = 180°- 119° = 61°

Since KO is the angle bisector of ∠JKN,

m∠JKP = \frac{1}{2}(\angle JKN)

            = \frac{1}{2}(61)

            = 30.5°

6 0
3 years ago
3. Continue the pattern with 4 fifths.
Elenna [48]

Answer:

I don’t have enough context clues to answer your question I’m afraid

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Is 4y=16x a Direct variation
gizmo_the_mogwai [7]

In the given equation, as the value of <em>y</em> increase, the value of <em>x</em> also

increases.

  • Yes, 4·y = 16·x is a direct variation

Reasons:

A direct variation is a relationship that exists between two variables. It is

also known as a direct proportion which can be expressed as; y = k·x

Where <em>k</em> is a number

The given equation is 4·y = 16·x

Dividing both sides by 4 gives;

\displaystyle \frac{4 \cdot y}{4}  = \frac{16 \cdot x}{4} = \frac{4 \times 4 \cdot x}{4}

Which gives;

y = 4·x

Comparing the above equation with the equation for a direct variation gives;

y = 4·x

y = k·x

Therefore;

k = 4

The equation, y = 4·x, and therefore, the equation from which it is derived, 4·y = 16·x, is a direct variation.

Learn more about direct variation here:

brainly.com/question/6499629

6 0
2 years ago
Can someone answer number 16 PLEASE
-Dominant- [34]

Answer:

If i am correct it should be 34

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Other questions:
  • Express in rectangular form (7(cos 85 degrees + isin 85 degrees))x(2(cos 95 degrees + i sin 95 degrees))
    12·1 answer
  • Dimitri is paid 8 percent commission on his total sales every pay period. Last pay period, he sold $6,300 worth of items. After
    10·2 answers
  • Steven wants to fill a 20gallon tank with water. If he uses2 1/2 gallon container to fill the tank, how many times must the cont
    12·2 answers
  • What times 6 equals 64
    14·2 answers
  • A shareholders' group, in lodging a protest, claimed that the mean tenure for a chief executive office (CEO) was at least eight
    15·1 answer
  • What is the area of a triangle whose vertices are P(−1, 4), Q(3, 2), and R(3, −4)?
    9·1 answer
  • (5+5i)(5-5i)=what????
    12·2 answers
  • Select all the ways 7/12, 1 whole, and 1 whole can be decomposed.
    13·1 answer
  • Dana is given the total surface area of a rectangular pyramid. She is asked for the lateral surface area. Describe how Dana can
    11·1 answer
  • Para las celebraciones del barrio de Santiago se junto cierta cantidad de dinero que se distribuirá de la siguiente forma:?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!