To find the median, we will list our numbers from least to greatest, and then cross out the smallest number and the biggest number. 0,0,1,3,3,4,5,5,7,7,7,7,7,10,18,50. 0,1,3,3,4,5,5,7,7,7,7,7,10,18. 1,3,3,4,5,5,7,7,7,7,7,10. 3,3,4,5,5,7,7,7,7,7. 3,4,5,5,7,7,7,7. 4,5,5,7,7,7. 5,5,7,7. 5,7. Since we cannot find a middle number, add the last two numbers up and divide by 2. 5+7 = 12. 12/2=6. Our median is 6. The mean is the sum of all numbers divided by how many numbers we have. 0+0+1+3+3+4+5+5+7+7+7+7+7+10+18+50= 132. We have 16 numbers total. 132/16 = 8.25. Our mean is 8.25. The mode is the number that appears the most within the given list. 7 appears the most. Your mode is 7. The range is the difference between the largest number and the smallest number. Our largest number is 50 and our smallest number is 0. The difference of two numbers means to subtract. Subtract 0 from 50. 50-0 = 50. Your range is 50. I hope this helps!
So first we factor 9-t^2=difference of 2 perfect squares a^2-b^2=(a-b)(a+b) 3^2-t^2=(3-t)(3+t)
t^2+t-12 factor by finding what 2 number add to get 1 and multiply to get -12 the numbers are -3 and 4 (t-3)(t+4)
[(3-t)(3+t)]/[(t-3)(t+4)] we can't factor out any further
if it was t^2-9 then we could go further but since it isn't this is the factored form (<u><em>if</em></u> it was t^-9 then the answer would be (t+3)/(t+4))
