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dexar [7]
3 years ago
6

Twenty-five sixth-grade students were asked to estimate how many hours a week they spend talking on the phone. This dot plot rep

resents their reported number of hours of phone usage per week.
Mathematics
1 answer:
RUDIKE [14]3 years ago
7 0

Answer:

where is the dot plot??

Step-by-step explanation:

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Does anybody know the answer?
kirill [66]

Answer:

y+48=90

y= 90-48

y= 42

Step-by-step explanation:

ok

by using the property

sum of two opposite interior angles of triangle is equal to exterior angle

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3 years ago
What is the answer to this math question?
Andrews [41]

Answer:

2x+a=5bx

Step 1: Add -2x to both sides.

a+2x+−2x=5bx+−2x

a=5bx−2x

Answer:

a=5bx−2x

Step-by-step explanation:

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Which describes the best relationship between the age of cheese and the amount of lactic acid present in the cheese
katrin2010 [14]
Positive correlation
6 0
3 years ago
First, complete the sentence to show how the figure can be decomposed into triangles and rectangles with the fewest number of pi
Whitepunk [10]

Answer: look below

Step-by-step explanation: answer 2 triangles 1 rectangle triangle Area is 6

For the rectangles is 16 and the combined area is 28!

6 0
3 years ago
If $8700 is invested at 3% annual simple interest, how much should be invested at 6% annual simple interest so that the total ye
True [87]
First off, see  how much 8700 as principal, yields at 3% APR
that is \bf \qquad \textit{Simple Interest Earned}\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$8700\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
t=years\to &1
\end{cases}

it will yield some amount

subtract that amount from 393
the difference is how much the yield will be on the 6% investment
so

\bf \qquad \textit{Simple Interest Earned}\\\\
I = Prt\quad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$8700\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
t=years\to &1
\end{cases}
\\\\\\
\implies \boxed{?}\\\\
-----------------------------\\\\
\textit{how much to invest at 6\%?}
\\\\\\


\bf \qquad \textit{Simple Interest Earned}\\\\
(393-\boxed{?}) = Prt\quad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$\\
r=rate\to 6\%\to \frac{6}{100}\to &0.06\\
t=years\to &1
\end{cases}
\\\\\\
\textit{solve for "P", to see how much should the Principal be}\\\\
\textit{keep in mind that }P+\boxed{?}=393\leftarrow \textit{both yields added}
6 0
3 years ago
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