Answer:
93% probability of a student taking a calculus class or a statistics class
Step-by-step explanation:
We solve this problem building the Venn's diagram of these probabilities.
I am going to say that:
A is the probability that a student takes a calculus class.
B is the probability that a student takes a statistics class.
We have that:

In which a is the probability that a student takes calculus but not statistics and
is the probability that a student takes both these classes.
By the same logic, we have that:

The probability of taking a calculus class and a statistics class is 0.07
This means that 
The probability of taking a statistics class is 0.90
This means that
. So



The probability of a student taking a calculus class is 0.10
This means that 



What is the probability of a student taking a calculus class or a statistics class

93% probability of a student taking a calculus class or a statistics class
Answer:
3/5
Step-by-step explanation:
Any number multiplied by it's reciprocal will get you the product of 1
(Can you mark me Brainliest)
Granny Smith was able to make 61.75 ounces of strawberry jelly
Using the binomial distribution, it is found that the variance of the number that pass inspection in one day is 5.7.
For each component, there are only two possible outcomes, either it passes inspection, or it does not. The probability of a component passing inspections is independent of any other component, hence, the binomial distribution is used to solve this question.
Binomial probability distribution
Probability of <u>exactly x successes on n repeated trials, with p probability</u>, and has variance given by:

In this problem:
- 95% pass final inspection, hence

- 120 components are inspected in one day, hence
.
The variance is given by:

The variance of the number that pass inspection in one day is 5.7.
To learn more about the binomial distribution, you can take a look at brainly.com/question/24863377
Answer:
18.75%
Step-by-step explanation:
Hello,
3 students are both female and senior
the total number of students is 7+10+8+5=30
so the probability to select one female senior is 3/30=1/10=0.10
probability to select one female is 16/30=16/30
probability that the student is a senior given that it's female is
=P(female and senior)/P(female)
=1/10*30/16=3/16
hope this helps