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Diano4ka-milaya [45]
3 years ago
8

Find the derivative. y = 5/ (2root4(x^3))

Mathematics
1 answer:
DedPeter [7]3 years ago
3 0
\bf y=\cfrac{5}{2\sqrt[4]{x^3}}\implies y=\cfrac{5}{2}\cdot x^{-\frac{3}{4}}\\\\
-----------------------------\\\\
\cfrac{dy}{dx}=\cfrac{5}{2}\left( -\cfrac{3}{4}x^{-\frac{3}{4}-1} \right)\implies 
\cfrac{dy}{dx}=\cfrac{5}{2}\left( -\cfrac{3}{4}x^{-\frac{7}{4}} \right)
\\\\\\
 
\cfrac{dy}{dx}=-\cfrac{15}{8}\cdot  x^{-\frac{7}{4}} 
\implies 
\cfrac{dy}{dx}=-\cfrac{15}{8}\cdot  \cfrac{1}{x^{\frac{7}{4}} }
\\\\\\


\bf
\cfrac{dy}{dx}=-\cfrac{15}{8x^{\frac{7}{4}}}\implies 
\cfrac{dy}{dx}=-\cfrac{15}{8\sqrt[4]{x^7}}\\\\\\ \cfrac{dy}{dx}=-\cfrac{15}{8x\sqrt[4]{x^3}}

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erma4kov [3.2K]

Answer:

0.48

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No

Yes

Step-by-step explanation:

Result of experiment :

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Total number of trials = 100

Recall :

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1.)

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2.)

P(Landing point down) = 52 / 100 = 0.52

3.)

The same result will not occur has the outcomes of trials aren't fixed.

4.) Yes, nearly the same result could occur on the second trial, as the number of possible outcubes are just 2 and the number if trials is high.

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Tems11 [23]

Answer:

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frutty [35]
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