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Diano4ka-milaya [45]
3 years ago
8

Find the derivative. y = 5/ (2root4(x^3))

Mathematics
1 answer:
DedPeter [7]3 years ago
3 0
\bf y=\cfrac{5}{2\sqrt[4]{x^3}}\implies y=\cfrac{5}{2}\cdot x^{-\frac{3}{4}}\\\\
-----------------------------\\\\
\cfrac{dy}{dx}=\cfrac{5}{2}\left( -\cfrac{3}{4}x^{-\frac{3}{4}-1} \right)\implies 
\cfrac{dy}{dx}=\cfrac{5}{2}\left( -\cfrac{3}{4}x^{-\frac{7}{4}} \right)
\\\\\\
 
\cfrac{dy}{dx}=-\cfrac{15}{8}\cdot  x^{-\frac{7}{4}} 
\implies 
\cfrac{dy}{dx}=-\cfrac{15}{8}\cdot  \cfrac{1}{x^{\frac{7}{4}} }
\\\\\\


\bf
\cfrac{dy}{dx}=-\cfrac{15}{8x^{\frac{7}{4}}}\implies 
\cfrac{dy}{dx}=-\cfrac{15}{8\sqrt[4]{x^7}}\\\\\\ \cfrac{dy}{dx}=-\cfrac{15}{8x\sqrt[4]{x^3}}

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