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Eduardwww [97]
3 years ago
9

Assume that adults have iq scores that are normally distributed with a mean of 100 and a standard deviation of 20. if all iq sco

res are converted to z-scores, what would the mean and standard deviation of all z scores be
Mathematics
1 answer:
Svetlanka [38]3 years ago
6 0

Let X be the iq score of adults. X is normally distributed with mean of 100 and standard deviation of 20.

If all iq scores are converted to z -scores then we will get z scores. And the z score is standard normal variable with mean=0 and standard deviation =1

Hence the mean and standard deviation of of all z scores will be 0 and 1 respectively.

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Leo's bank balances at the end of months 1, 2, and 3 are $1500, $1530, and $1560.60,
grandymaker [24]

Leo's balance after 9 months will be: $1757.49

Step-by-step explanation:

It is given that the balances follow a geometric sequence

First of all, we have to find the common ratio

Here

a_1 = 1500\\a_2 = 1530\\a_3 = 1560.60

Common ratio is:

r = \frac{a_2}{a_1} = \frac{1530}{1500} = 1.02\\r = \frac{a_3}{a_2} = \frac{1560.60}{1530} = 1.02

So r = 1.02

The general form for geometric sequence is:

a_n = a_1r^{n-1}

Putting the first term and r

a_n = 1500 . (1.02)^{n-1}

To find the 9th month's balance

Putting n=9

a_9 = 1500 . (1.02)^{9-1}\\= 1500.(1.02)^8\\=1757.4890

Rounding off to nearest hundredth

$1757.49

Hence,

Leo's balance after 9 months will be: $1757.49

Keywords: Geometric sequence, balance

Learn more about geometric sequence at:

  • brainly.com/question/10772025
  • brainly.com/question/10879401

#LearnwithBrainly

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