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cupoosta [38]
2 years ago
9

What is 4/9 closest to 0,1/2 or 1

Mathematics
2 answers:
madam [21]2 years ago
7 0
The correct answer is 0.44 which is closer to 0.5
topjm [15]2 years ago
4 0

Answer:

1/2

Step-by-step explanation:

4/9 is equal to 4.444 repeating so that would be closest to 1/2

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Convert 18 centimeters per second to meters per hour.<br> hint: 1 m = 100 cm
denis-greek [22]

Answer:

The answer to your question is 648 m/h

Step-by-step explanation:

           

                  \frac{18 cm}{s} \frac{1 m}{100 cm} \frac{3600 s}{1 h}

                  \frac{(18)(1)(3600)}{(1)(100)(1)}

                  \frac{64800}{100}

                          = 648 m/h

3 0
3 years ago
Read 2 more answers
PLEASE can someone explain why The exact value of sec ( π/6) is 2 /√ 3 ??
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3 0
3 years ago
How do you Graph y= x + 4
Marrrta [24]

put x=0 then y=4

put y=0 then x=-4

therefore 2 ccordintes are

(0,4) and (-4,0)

take a scale and construct a line joining these two points.

you will get the required graph.

hope it helps.

please follow if you like.

8 0
3 years ago
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50 POINTS!
padilas [110]
To double the principle the formula is
2p=p e^rt
2=e^rt
2=e^0.12t
Solve for t
T=(log(2)÷log(e))÷0.12
T=5.78 years
5 0
3 years ago
Hiro bought a small carton of milk at lunch. If the approximate dimensions of the milk carton are shown what is the minimum amou
faltersainse [42]

Answer:

C.\ 104\ in^2

Step-by-step explanation:

At first, the question looks like an optimization problem, but since all the dimensions of the carton are given, we only have to compute the total area of the given figure.

Let's calculate the front (and back) areas, which are rectangles

A_1=(6.5)(3)=19.5\ in^2

Now with the lateral rectangles which happen to have the very same dimensions

A_2=19.5\ in^2

Next, we compute the front and back triangles of base 3 in and height 1.5 in

A_3=\frac{1}{2}(3)(1.5)=2.25\ in^2

Now, the lateral inclined rectangles of base 3 in and height 2 in

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Finally, the base rectangle who happens to be a square of side 3 in

A_5=(3)(3)= 9\ in^2

This last area, unlike all others, is not doubled because its counterpart is inside the carton and is not part of the lateral area

Our total area of cardboard is

A_t=2(19.5)+2(19.5)+2(2.25)+2(6)+9=103.5\ in^2

The closest option to this answer is

C.\ 104\ in^2

5 0
3 years ago
Read 2 more answers
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