Answer:
1. D. 20, 30, and 50
2. A. 86
3. B. 94
Step-by-step explanation:
1. To find the outliers of the data set, we need to determine the Q1, Q3, and IQR.
The Q1 is the middle data in the lower part (first 10 data values) of the data set (while the Q3 is the middle data of the upper part (the last 10 data values) the data set.
Since it is an even data set, therefore, we would look for the average of the 2 middle values in each half of the data set.
Thus:
Q1 = (85 + 87)/2 = 86
Q3 = (93 + 95)/2 = 94
IQR = Q3 - Q1 = 94 - 86
IQR = 8
Outliers in the data set are data values below the lower limit or above the upper limit.
Let's find the lower and upper limit.
Lower limit = Q1 - 1.5(IQR) = 86 - 1.5(8) = 74
The data values below the lower limit (74) are 20, 30, and 50
Let's see if we have any data value above the upper limit.
Upper limit = Q3 + 1.5(IQR) = 94 + 1.5(8) = 106
No data value is above 106.
Therefore, the only outliers of the data set are:
D. 20, 30, and 50
2. See explanation on how to we found the Q1 of the given data set as explained earlier in question 1 above.
Thus:
Q1 = (85 + 87)/2 = 86
3. Q3 = (93 + 95)/2 = 94
Answer:
i think it is c.
Step-by-step explanation:
i hope you get it right, i'll keep my fingers crossed.
R= diameter/2
answer: 8 units
Answer: 0.44mm
Step-by-step explanation:
In this problem we are asked for the height of a single playing chip. We know the volume of a cylinder is 25120 mm^3.
V=πr²h
25120=πr²h
The problem also gives the diameter of the case: 40mm.
To find radius, you divide the diameter in half.
d=2r
40=2r
r=20
With the radius, we can add that to the volume equation.
25120=(20)^2h
25120=400πh
All we have left is to find the height.
h=25120/(400π)
h≈20mm
Now that we know the height, we can find the height of a single chip. The problem states about 50 chips can fit in a case. To find the height of a single chip, you would divide 20 by 50.
20mm/50 chips=0.4mm/chip.