Answer:
The correct answers are A. "crenation", B. "hemolysis", C. "hemolysis", D. "crenation" and E. "neither will occur".
Explanation:
0.9% (m/v) NaCl or 5.0% (m/v) glucose are isotonic solutions at which the cells will not suffer any harmful consequence. A solution with a higher concentration than the isotonic conditions would result in the cells crenation, while a solution with a lower concentration would result in the cells hemolysis. Therefore the consequences of putting the red cells to the solutions stated in the question are as following:
A: 3.21% (m/v) NaCl Solution = crenation (higher than 0.9% (m/v) NaCl)
B: 1.65% (m/v) glucose Solution = hemolysis (lower than 5.0% (m/v) glucose)
C: distilled H2O Solution = hemolysis (lower than 0.9% (m/v) NaCl or 5.0% (m/v) glucose)
D: 6.97% (m/v) glucose Solution = crenation (higher than 5.0% (m/v) glucose)
E: 5.0% (m/v) glucose and 0.9%(m/v) NaCl = neither will occur (equal to 5.0% (m/v) glucose and 0.9% (m/v) NaCl)
Because it carries a lot of blood to the arteries
Answer:
Weathering look at the text book mate
The regression equation is:
y = 1.15 – 0.251 x₁ + 0.078 x₂ + 0.306 x₁x₂
<span>
<span>
<span>
Where,
x₁ = -0.2508
x₂ = 0.0777
x₁x₂ = 0.3058
Inserting the values,
<span>
<span>
</span></span>y = 1.15 – {0.251 × (-0.2508)} + {0.078 ×(0.0777)} + {0.306 × (0.3058)}
</span></span></span>
y = 1.15 - (- 0.0629508) + 0.0060606 + 0.935748
y = 1.15 + 0.0629508 + 0.0060606 + 0.935748
y = 1.3125862
Answer:
x₁ and x₂ are main effects (a type of tuna and type of packing liquid) that contribute significant information for the prediction of <span>y.</span>
Objects with like charges repel/repulse each other while opposite charges attract each other
The direction of an electric fields is alway the direction electrons would naturally move.
Not sure about the last one, my gut instinct is opposite.