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3 years ago

15

joe ran half the distance that Phil did. If the distance that Phil ran is represented by r, which expression represents the dist

ance that Joe ran?

2 answers:

wel3 years ago

5 0

Answer:

r/2

Step-by-step explanation:

VladimirAG [237]3 years ago

4 0

Answer:

r/2

Step-by-step explanation:

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A survey showed that 7/15 of a class liked soccer and 2/5 liked baseball. Which sport was liked LESS?

vichka [17]

2/5 will be the answer

6 0

3 years ago

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Members of the student concil are conducting a fundraiser by selling school calendars. After selling 80 calendars, they had a lo

Oksana_A [137]

Answer:

a) $y=8x-1000$

b) $profit=\$8$

c) They'd have lost $1000 if they had sold no calendars.

Step-by-step explanation:

a) The equation of the line in Slope-Intercept form is:

$y=mx+b$

Where "m" is the slope and "b" is the y-intercept.

In this case we know that "y" represents the profit of loss and "x" the number of calendars sold.

Then, according to the exercise, the line passes through these two points:

$(80,-360)$ and $(200,600)$

Then, we can find the slope of the line with the formula $m=\frac{y_2-y_1}{x_2-x_1}$

$m=\frac{-360-600}{80-200}=8$

Now, we can substitute the slope and one of those points into $y=mx+b$ and solve for "b":

$600=8(200)+b\\\\b=-1000$

Then, subtituting values, we get that the equation that describes the relation between the profit of loss and the number of calendars sold, is:

$y=8x-1000$

b) The slope of the line is the profit they made from selling each calendar

$profit=8$

c) The y-intercept is the amount they would have lost if they had sold no calendars:

$b=-1000$

They'd have lost $1000 if they had sold no calendars.

6 0

3 years ago

X - 6 = 8 what is x?

kondor19780726 [428]

Answer:

$x = 14$

Step-by-step explanation:

$x - 6 = 8$
Group like terms.
$x = 8 + 6$
$x = 14$

5 0

3 years ago

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Pleaseee helppp with thissss asapppp

Natasha2012 [34]

As we know that the standard equation of circle is ${\bf{(x-h)^{2}+(y-k)^{2}=r^{2}}}$ , where <em>r</em> is the radius of circle and centre at <em>(h,k) </em>

Now , as the circle passes through <em>(2,9)</em> so it must satisfy the above equation after putting the values of <em>h</em> and <em>k</em> respectively

${:\implies \quad \sf \{2-(-1)\}^{2}+(9-5)^{2}=r^{2}}$

${:\implies \quad \sf (3)^{2}+(4)^{2}=r^{2}}$

${:\implies \quad \sf 9+16=r^{2}}$

After raising ½ power to both sides , we will get <em>r = +5 , -5</em> , but as radius can never be -<em>ve</em> . So <em>r = +</em><em>5</em><em> </em>

Now , putting values in our standard equation ;

${:\implies \quad \sf \{x-(-1)\}^{2}+(y-5)^{2}=(5)^{2}}$

${:\implies \quad \bf \therefore \quad \underline{\underline{(x+1)^{2}+(y-5)^{2}=25}}}$

<em>This is the required equation of </em><em>Circle</em>

Refer to the attachment as well !

8 0

2 years ago

5. Landon bought a new car for $16,000 and it depreciates 4.5% every year. Write a function that describes

snow_tiger [21]

Answer:

<h3>The value C(t) of the car after 5 years is $12709.</h3>

Step-by-step explanation:

Given that Landon bought a new car for $16,000 and it depreciates 4.5% every year.

<h3>To find the value C(t) of the car after 5 years:</h3>

Initial value $C(0)= $16,000$

Depreciation rate is $r=\frac{4.5}{100}$

<h3>∴ r=0.045</h3>

Period , t=5 years

$C(t)=C(0)(1-r)^t$

Substitute the values we get

$C(5)=16000(1-0.045)^5$

$=16000(0.955)^5$

$=16000(0.7943)$

∴ $C(5)=12708.8$

<h3>The value C(t) of the car after 5 years is $ 12709</h3>

3 0

3 years ago