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3 years ago

Help? Will give brainliest!

Mathematics

1 answer:

Alex Ar [27]3 years ago

5 0

Answer:

Top one

Step-by-step explanation:

It is more appropriate to measure the speck of dust using millimeters because that is most similar to the scale of the speck's size.

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Aight ok so if i got two ducks and and i take one how munch is left

vichka [17]

Answer:

Step-by-step explanation:

5 0

4 years ago

Read 2 more answers

What is the y intercept of y=7-2x

neonofarm [45]

Answer: It would be 7. (0,7)

4 0

3 years ago

Theo bought 2 hot dogs and two drinks for $4.00. At the same concession stand, Vicky bought 3 hot dogs and a drink for $4.50. Wr

Sedbober [7]

Answer:

The hot dog are $2.63

Step-by-step explanation:

Hot Dogs = H

Drinks = D

2H + 2D = 4

Divide both sides by 2

H + D = 2

Subtract D from either side

H = 2 -D

3H + D = 4.50

Plug in 2 - D for H

3(2- D ) + D = 4.50

6 - 3D + D = 4.50

6 - 4D = 4.50

Add 6 to either side

-4D = 10.50

Divide either side by -4

D = -2 . 625

3 0

3 years ago

How many times greater is The total area of Russia than the total area of Finland? Finland total area is 3.4 x 10 to the 5th pow

Luden [163]

Answer:

The answer to your question is Russia is 50 times greater than Finland.

Step-by-step explanation:

Data

Finland area = 3.4 x 10⁵ km²

Russia area = 1.7 x 10⁷ km²

Proportion = ?

Process

1.- Just divide the Russia's area by the Finland's area.

Proportion = $\frac{Finland's area}{Russia's area}$

Proportion = $\frac{1.7 x 10^{7} }{3.4 x 10^{5} }$

Porportion = 50

6 0

3 years ago

WILL GIVE BRAINLIEST& 15 PTS.

kicyunya [14]

Answer:

The given fraction $\frac{x^3-x^2}{x^3}$ reduces to $\frac{x-1}{x}$

Step-by-step explanation:

Consider the given fraction $\frac{x^3-x^2}{x^3}$

We have to reduce the fraction to the lowest terms.

Consider numerator $x^3-x^2$

We can take x² common from both the term,

Thus, numerator can be written as $x^2(x-1)$

Given expression can be rewritten as ,

$\frac{x^3-x^2}{x^3}=\frac{x^2(x-1)}{x^3}$

We can now cancel $x^2$ from both numerator and denominator,

$\Rightarrow \frac{x^2(x-1)}{x^3}=\frac{x^2(x-1)}{x^2 \cdot x}$

$\Rightarrow \frac{(x-1)}{x^2 \cdot x}=\frac{x-1}{x}$

Thus, the given fraction $\frac{x^3-x^2}{x^3}$ reduces to $\frac{x-1}{x}$

6 0

3 years ago

Read 2 more answers