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ValentinkaMS [17]
3 years ago
6

True or false: The mode is universally an accurate representation of data sets because it captures the number that occurs most o

ften.
Mathematics
1 answer:
DiKsa [7]3 years ago
7 0

Answer:

False

Step-by-step explanation:

Actually, the second side of the question is true. Yes, mode is the most frequent and often number captures the data set. But, it could not be said about the accurate and universal data sets representation. Because:

1) Sometimes mode might not be unique, it may have more than one so we will be stuck about choosing the best representation.

2) Or, if we have continuous data, we will have a lot of values so it will be tough to determine.

3) The problem of not being available to provide the very good measure of the central tendency. It happens, for instance, the mark mostly seen is very far from the rest of the data.

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horsena [70]
2x+4(2x+7)+3(2x+4)
2x+8x+28+6x+12
16x+40

16x+40 would be the answer you can’t solve it any further
4 0
3 years ago
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Solve for d.<br> d + 67 = 87<br> р<br> Submit
Vsevolod [243]

Answer:

d=20

Step-by-step explanation:

d+67=87

Subtract 67 from both sides

d=20

Hope this is helpful

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3 years ago
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Given f(x)=x-10. what is f(-7)
Vlad [161]
f( - 7) = ( - 7) - 10 \\ = -1 7
answer is -17
5 0
3 years ago
Choose whether it's always, sometimes, never 
Keith_Richards [23]

Answer: An integer added to an integer is an integer, this statement is always true. A polynomial subtracted from a polynomial is a polynomial, this statement is always true. A polynomial divided by a polynomial is a polynomial, this statement is sometimes true. A polynomial multiplied by a polynomial is a polynomial, this statement is always true.

Explanation:

1)

The closure property of integer states that the addition, subtraction and multiplication is integers is always an integer.

If a\in Z\text{ and }b\in Z, then a+b\in Z.

Therefore, an integer added to an integer is an integer, this statement is always true.

2)

A polynomial is in the form of,

p(x)=a_nx^n+a_{n-1}x^{x-1}+...+a_1x+a_0

Where a_n,a_{n-1},...,a_1,a_0 are constant coefficient.

When we subtract the two polynomial then the resultant is also a polynomial form.

Therefore, a polynomial subtracted from a polynomial is a polynomial, this statement is always true.

3)

If a polynomial divided by a polynomial  then it may or may not be a polynomial.

If the degree of numerator polynomial is higher than the degree of denominator polynomial then it may be a polynomial.

For example:

f(x)=x^2-2x+5x-10 \text{ and } g(x)=x-2

Then \frac{f(x)}{g(x)}=x^2+5, which a polynomial.

If the degree of numerator polynomial is less than the degree of denominator polynomial then it is a rational function.

For example:

f(x)=x^2-2x+5x-10 \text{ and } g(x)=x-2

Then \frac{g(x)}{f(x)}=\frac{1}{x^2+5}, which a not a polynomial.

Therefore, a polynomial divided by a polynomial is a polynomial, this statement is sometimes true.

4)

As we know a polynomial is in the form of,

p(x)=a_nx^n+a_{n-1}x^{x-1}+...+a_1x+a_0

Where a_n,a_{n-1},...,a_1,a_0 are constant coefficient.

When we multiply the two polynomial, the degree of the resultand function is addition of degree of both polyminals and the resultant is also a polynomial form.

Therefore, a polynomial subtracted from a polynomial is a polynomial, this statement is always true.

3 0
3 years ago
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QUICK
katrin [286]

Answer:

7502.88m^2

here u go hope it helps

7 0
3 years ago
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