Answer:
The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors
P(X⁻ ≥ 96.3) = 0.0087
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that the mean of the Population = 95
Given that the standard deviation of the Population = 5
Let 'X' be the random variable in a normal distribution
Let X⁻ = 96.3
Given that the size 'n' = 84 monitors
<u><em>Step(ii):-</em></u>
<u><em>The Empirical rule</em></u>


Z = 2.383
The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors
P(X⁻ ≥ 96.3) = P(Z≥2.383)
= 1- P( Z<2.383)
= 1-( 0.5 -+A(2.38))
= 0.5 - A(2.38)
= 0.5 -0.4913
= 0.0087
<u><em>Final answer:-</em></u>
The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors
P(X⁻ ≥ 96.3) = 0.0087
3x = x / 2
Mmc (2,1) = 2
6x = x
6x- x = 0
5x= 0
x = 0/5
x = 0
Answer:
Given:
.
Assuming that
,
while
.
Step-by-step explanation:
By the Pythagorean identity
.
Assuming that
,
.
Rearrange the Pythagorean identity to find an expression for
.
.
Given that
:
.
Hence,
would be:
.
Answer:
$60
Step-by-step explanation:
12/8 = x/40
40(12/8) = x
60 = x
The equation x^2 - 6x + 9 is a perfect square and when factored out it becomes C. ) It is a perfect square (x - 3)^2