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3 years ago

8

List of solid mixtures in your classroom

1 answer:

Vadim26 [7]3 years ago

4 0

<span>Two examples of solid mixtures in a classroom are wax on the floor and paint on the wall.</span>

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A 55 kilogram person jumps off a cliff and hits the water 5.8 seconds later, how high is the cliff above the water?

ElenaW [278]

R=ut+gt^2/2
r- displacement (height to find)
u - initial speed (zero)
t - time taken

r=0*5.8 + 10*5.8^2 /2 = 168.2 meters

8 0

3 years ago

Which group of animals would be served best by the following adaptations?

aev [14]

The answer to this question would be: <span>A) animals that live in deserts

</span>Desert temperature is high, especially in the day, <span>An animal that lives in the desert needs to adapt to the high temperature either by reducing the heat or by increasing heat loss. By becoming nocturnal, the animal also able to evade the sunlight so it was less exposed to the heat.
Unlike other option, the desert is lacking water. Desert is mostly dry and water would be a resource that hard to find. In this case, k</span><span>idneys adapted to check water loss would be a great help</span>

5 0

3 years ago

Read 2 more answers

Two charges are placed on the x axis. One of the charges (q1 = +7.7 µC) is at x1 = +3.1 cm and the other (q2 = -19 µC) is at x2

Alinara [238K]

Answer:

a) $E=50.53\times 10^{6}\ N/C$

The direction will be negative direction.

b) $E=268.22\times 10^{6}\ N/C$

The direction will be positive direction.

Explanation:

Given that

q1 = +7.7 µC is at x1 = +3.1 cm

q2 = -19 µC is at x2 = +8.9 cm

We know that electric filed due to a charge given as

$E=K\dfrac{q}{r^2}$

$E_1=K\dfrac{q_1}{r_1^2}$

$E_2=K\dfrac{q_2}{r_2^2}$

Now by putting the va;ues

a)

$E_1=9\times 10^9\times \dfrac{7.7\times 10^{-6}}{0.031^2}\ N/C$

$E_1=72.11\times 10^{6}\ N/C$

$E_2=9\times 10^9\times \dfrac{19\times 10^{-6}}{0.089^2}\ N/C$

$E_2=21.58\times 10^{6}\ N/C$

The net electric field

$E=E_1-E_2$

$E=50.53\times 10^{6}\ N/C$

The direction will be negative direction.

As we know that electric filed line emerge from positive charge and concentrated at negative charge.

b)

Now

distance for charge 1 will become =5.5 - 3.1 = 2.4 cm

distance for charge 2 will become =8.9-5.5 = 3.4 cm

$E_1=9\times 10^9\times \dfrac{7.7\times 10^{-6}}{0.024^2}\ N/C$

$E_1=120.3\times 10^{6}\ N/C$

$E_2=9\times 10^9\times \dfrac{19\times 10^{-6}}{0.034^2}\ N/C$

$E_2=147.92\times 10^{6}\ N/C$

The net electric field

$E=E_1+E_2$

$E=268.22\times 10^{6}\ N/C$

The direction will be positive direction.

7 0

3 years ago

People often use simple machines like pulleys, levers, and ramps because they say the machine “makes the work easier.” Which of

dimulka [17.4K]

I think the answer is D.
Hope this help

3 0

3 years ago

What are the six different character traits scientists should have?

frozen [14]

careful observation, curiosity, logic, creativity, skepticism, and objectivity

3 0

3 years ago

Read 2 more answers