Your cat "Ms." (mass 7.00 {\rm kg}) is trying to make it to the top of a frictionless ramp 2.00 {\rm m} long and inclined upward
at 30.0 ^\circ above the horizontal. Since the poor cat can't get any traction on the ramp, you push her up the entire length of the ramp by exerting a constant 100 {\rm N} force parallel to the ramp.
If Ms. takes a running start so that she is moving at 2.40 {\rm m/s} at the bottom of the ramp, what is her speed when she reaches the top of the incline? Use the work-energy theorem.
If Ms. takes a running start so that she is moving at 2.40 {\rm m/s} at the bottom of the ramp, what is her speed when she reaches the top of the incline? Use the work-energy theorem.
1 answer:
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Explanation:
Given parameters:
Initial velocity = 72km/hr
Final velocity = 0km/hr
Time taken = 25s
Unknown:
Acceleration = ?
Solution:
To solve this problem, convert km/hr to m/s;
1000m = 1km
3600s = 1hr
72km/hr;
1km/hr = 0.278m/s
72km/hr = 0.278 x 72 = 20.02m/s
Acceleration is the change in velocity divided by the time taken;
Acceleration =
Acceleration = = -0.8m/s
The car is actually decelerating at a rate of 0.8m/s