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Verizon [17]
3 years ago
8

A roast turkey is taken from an oven when its temperature has reached 185°F and is placed on a table in a room where the tempera

ture is 75°F. The graph shows how the temperature of the turkey decreases and eventually approaches room temperature. By measuring the slope of the tangent, estimate the rate of change of the temperature after an hour.
Physics
2 answers:
skelet666 [1.2K]3 years ago
6 0
<span>Vertical lines are 50º apart. Horizontal lines are 30 minutes apart.</span>
Mazyrski [523]3 years ago
5 0
Solve the Diffeq to get: 
<span>T(t) = Tₐ + (T₀ - Tₐ)∙e^(-kt) </span>

<span>T₀ is the initial temperature of the object = 185°F </span>
<span>Tₐ is the ambient temperature = 75°F </span>

<span>Unfortunately, you have not been given enough information to solve this problem. You'll need a k-value for turkey in order to solve this or another equation in which you can solve for k. </span>

<span>If you assume k ≈ 0.4 like this question (see below), then: </span>

<span>90 = 75 + 110∙e^(-0.4t) </span>

<span>t ≈ 4.98 minutes
</span>It depends on what unit of k had

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2 years ago
1. A mass is on a level plane, it has a weight of 20N. What is the coefficient of kinetic friction if an applied force
Arturiano [62]

Answer:

0.4

Explanation:

F-Fr=ma where F is applied force, Fr is friction, m is mass and a is acceleration.

Since the mass is moving with a constant velocity, there's no acceleration hence

F=Fr=\mu N where N is the weight of object and \mu is coefficient of kinetic friction.

F=\mu N and making [tex]\mu the subject

\mu=\frac {F}{N}

Substituting F for 8 N and N for 20 N

\mu=\frac {8}{20}=0.4

Therefore, coefficient of kinetic friction is 0.4

4 0
3 years ago
Would it be better to collide head-on with an identical car traveling at the same speed or collide with a stationary brick wall?
attashe74 [19]
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6 0
3 years ago
A proton initially moves left to right along the x-axis at a speed of 2.00 x 103 m/s. It moves into an uniform electric field, w
FinnZ [79.3K]

Answer:

E = 1.04*10⁻¹ N/C

Explanation:

Assuming no other forces acting on the proton than the electric field, as this is uniform, we can calculate the acceleration of the proton, with the following kinematic equation:

vf^{2} -vo^{2} = 2*a*x

As the proton is coming at rest after travelling 0.200 m to the right,  vf = 0, and x = 0.200 m.

Replacing this values in the equation above, we can solve for a, as follows:

a = \frac{vo^{2}*mp}{2*x} = \frac{(2.00e3m/s)^{2}}{2*0.2m} = 1e7 m/s2

According to Newton´s 2nd Law, and applying the definition of an electric field, we can say the following:

F = mp*a = q*E

For a proton, we have the following values:

mp = 1.67*10⁻²⁷ kg

q = e = 1.6*10⁻¹⁹ C

So, we can solve for E (in magnitude) , as follows:

E = \frac{mp*a}{e} =\frac{1.67e-27kg*1e7m/s2}{1.6e-19C} = 1.04e-1 N/C

⇒ E = 1.04*10⁻¹ N/C

5 0
3 years ago
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