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lana [24]
3 years ago
6

Rutherford's gold foil experiment revealed the atom has what subatomic particle

Physics
1 answer:
musickatia [10]3 years ago
3 0
His gold foil experiment revealed the atom had a dense positive subatomic particle in the middle . He called it the NUCLEUS.

Hope this helps!
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A summary of a source is usually
Mekhanik [1.2K]

Answer:

A shorter than the original source and in the researcher's words

Explanation:

The summary is an abridged version of the original source and in the researcher's own very words.

Summaries gives an over-arching perspective and excludes implicit details from a given text.

A summary should not be detailed and must avoid overt illustrations. They must capture the true essence of piece leaving out flowery details.

A summary should be lesser in length than the original piece. Any third party reader should immediately be able to grab the details of the original piece from the summary.

5 0
3 years ago
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What is the answer to 17 ‐ 12× ‐ 18 ‐ 5×
Nastasia [14]
The answer is -17x-1. You have to combine like terms.
7 0
4 years ago
How is a force multiplied in a hydraulic<br> system?
HACTEHA [7]

Answer:

Pascal's law states that when there is an increase in pressure at any point in a confined fluid, there is an equal increase at every other point in the container. ... Applied to a more complex system below, such as a hydraulic car lift, Pascal's law allows forces to be multiplied.

Explanation:

4 0
3 years ago
In her hand, a softball pitcher swings a ball of mass 0.245 kg around a vertical circular path of radius 59.8 cm before releasin
GuDViN [60]

Answer:

The velocity is v_b = 20.17 \ m/s

Explanation:

From the question we are told that

   The mass of the ball is  m = 0.245 \ kg

   The radius is  r =  59.8 \  cm  =  0.598 \ m

   The force is  F =  30.9 \ N

   The speed of the ball is  v = 16.0 \ m/s.

Generally the kinetic energy at the top of the circle is mathematically represented as

    K_t  =  \frac{1}{2} *  m  *  v^2

=> K_t  =  \frac{1}{2} *  0.245   *  16.0 ^2  

=> K_t  =  31.36 \ J  

Generally the work done by the force applied on the ball from the top to the bottom  is mathematically represented as

       W =  F *  d

Here  d is the length of  a semi - circular arc which is mathematically represented as

       d =  \pi * r

So

      W =  30.9 *  0.598

      W = 18.48 \ J

Generally the kinetic energy at the bottom is mathematically represented as

      K_b  =  \frac{1}{2} *  m *  v_b^2

=>    K_b  =  \frac{1}{2} *  0.245  *  v_b^2

=>   K_b  =  0.1225  *  v_b^2

From the law of energy conservation

     K_t +  W  =K_b

=>    31.36+  18.48 = 0.1225  *  v_b^2

=>    v_b = 20.17 \ m/s

3 0
3 years ago
what is the total magnification of a microscope with an eyepiece magnification of 10x and an objective lens magnification of 50x
Anon25 [30]

Answer:

500x

Explanation:

A microscope had an eyepiece magnification of 10x

The objective lens magnification is 50x

Therefore the total magnification can be calculated as follows

= 10 × 50

= 500x

Hence the total Magnificattion is 500x

8 0
3 years ago
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