Class A: 6v + 8b = 202
Class B: 12v + 16b = 284
Solve using the elimination method:
since 6v and 12v are perfect for elimination, multiply the class A equation by 2 so that the van variable cancels out:
12v + 16b = 404
12v + 10b = 284
Then subtract the bottom equation from the top:
6b = 120
b = 20
Now you know that each bus can hold 20 students.
Just plug this into one of the original equations to solve for vans:
6v + 8(20) = 202
6v + 160 = 202
6v = 42
v=7
So then you know that each van can hold 7 students.
Check:
12 (7) + 10 (20) = 284
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I believe -4 hope this helped
Answer:
z=3.8196
Step-by-step explanation:
-We notice that this is a normal distribution problem.
-Given the mean is $8500, standard deviation is $1200 , and n=350, the critical z-value using alpha=0.05 is calculated as:
Hence, the test statitic is z=3.8196
Answer:
70 degrees
Step-by-step explanation:
The adjacent angles in a parallelogram are supplementary and add to 180 degrees
∠CDE+∠DEF=180
We know that ∠CDE is 110 degrees, so we can substitute that in
∠CDE+∠DEF=180
110+∠DEF=180
Subtract 110 from both sides
∠DEF= 70
So, ∠E is 70 degrees
Answer:
16m and 12m
Step-by-step explanation:
2x + 2(x - 4) = 56
4x = 64
x = 16
Sides are 16 m and 12 m
