Answer:
f(x) is shifted to the left 2 units of g(x)
f(x) will not be shifted vertically since we did not add anything to g(x)
Step-by-step explanation:
g(x) = x^2+2
f(x) = g(x+2)
When we shift with h(x+c) it is a horizontal shift
if c>0 it moves it left c units
if c< 0 it moves it right c units
Since c is 2, this is shifted left 2 units
f(x) is shifted to the left 2 units of g(x)
When we shift with h(x)+c it is a vertical shift
if c>0 it moves it up c units
if c< 0 it moves it down c units
f(x) will not be shifted vertically since we did not add anything to g(x)
Answer: MARK BRAINLIEST
23x
Step-by-step explanation:
x^3+x^2+5x+5 = 23x
Step-by-step explanation:
Apply Quoteint of Powers. Divide the intergers. serpately.
Note that Quotient of Powers is
So the answer is
The answer is
or
Problem 7)
The answer is choice B. Only graph 2 contains an Euler circuit.
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To have a Euler circuit, each vertex must have an even number of paths connecting to it. This does not happen with graph 1 since vertex A and vertex D have an odd number of vertices (3 each). The odd vertex count makes it impossible to travel back to the starting point, while making sure to only use each edge one time only.
With graph 2, each vertex has exactly two edges attached to it. So an Euler circuit is possible here.
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Problem 8)
The answer is choice B) 5
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Work Shown:
abc base 2 = (a*2^2 + b*2^1 + c*2^0) base 10
101 base 2 = (1*2^2 + 0*2^1 + 1*2^0) base 10
101 base 2 = (1*4 + 0*2 + 1*1) base 10
101 base 2 = (4 + 0 + 1) base 10
101 base 2 = 5 base 10
