Ask question

Ask question

All categories

3 years ago

14

thomas bought 3 dvds for 14.50 each a music cd for 9.99 and a computer game for 48. if the sles tax rate is 8.2% what is the tot

al cost of thomas purchases to the nearest cent

1 answer:

Galina-37 [17]3 years ago

4 0

Answer:$109.81

Step-by-step explanation:

You might be interested in

Solve for X (simplify your answer)

lora16 [44]

Answer:

x is given as -1.5. Substitute to confirm

7 0

3 years ago

HELP PLEASE ASAP<br> what is the mean of 210,160,200 ?

MrRissso [65]

To find the mean, add all the numbers then divide by the amount of numbers there are to find the average.

210+160+200=570

570÷3=190

Answer: 190

5 0

3 years ago

Read 2 more answers

PLEASE ANSWER I WILL GIVE BRAINLIEST!!!!

bixtya [17]

B.) 173 degrees

the answer is B

4 0

3 years ago

Given two independent random samples with the following results: n1=8x‾1=186s1=33 n2=7x‾2=171s2=23 Use this data to find the 90%

KonstantinChe [14]

Answer:

The point of estimate for the true difference would be:

$186-171= 15$

And the confidence interval is given by:

$(186-171) -1.77 \sqrt{\frac{33^2}{8} +\frac{23^2}{7}}= -10.753$

$(186-171) +1.77 \sqrt{\frac{33^2}{8} +\frac{23^2}{7}}= 40.753$

Step-by-step explanation:

For this case we have the following info given:

$\bar X_1 = 186$ the sample mean for the first sample

$\bar X_2 = 171$ the sample mean for the second sample

$s_1 =33$ the sample deviation for the first sample

$s_2 =23$ the sample deviation for the second sample

$n_1 = 8$ the sample size for the first group

$n_2 = 7$ the sample size for the second group

The confidence interval for the true difference is given by:

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2}\sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}$

We can find the degrees of freedom are given:

$df = n_1 +n_2 -2 =8+7-2= 13$

The confidence level is given by 90% so then the significance would be $\alpha=1-0.9=0.1$ and $\alpha/2=0.05$ we can find the critical value with the degrees of freedom given and we got:

$t_{\alpha/2}= \pm 1.77$

The point of estimate for the true difference would be:

$186-171= 15$

And replacing into the formula for the confidence interval we got:

$(186-171) -1.77 \sqrt{\frac{33^2}{8} +\frac{23^2}{7}}= -10.753$

$(186-171) +1.77 \sqrt{\frac{33^2}{8} +\frac{23^2}{7}}= 40.753$

5 0

3 years ago

What is the inverse of the statement below"

Sedaia [141]

The best option here is option A.

6 0

2 years ago