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aleksley [76]
3 years ago
6

One Algebra question. Thank you :D

Mathematics
2 answers:
Salsk061 [2.6K]3 years ago
5 0
The answer would be C because the coefficients are both perfect squares and when you subtract the exponents (6 - 4), it turns up to be an even number. (difference of exponents have to be an even number or zero)
vesna_86 [32]3 years ago
3 0
A^2 - b^2 ...difference of squares

so
9m^4 - 49n^6 = (3n^2)^2 - (7n^3)^2

answer
C. 9m^4 - 49n^6 


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Find an equation of the line having the given slope and containing the given point.
mart [117]

Answer:

y=8x-69

Step-by-step explanation:

you would use the equation y-y1 = m (x - x1)

plug in m = 8 , y1 = 3, x1 = 9

now you have y - 3 = 8 (x-9)

distribute 8 --> y-3 = 8x - 72

add three to both sides to get y = 8x - 69

6 0
2 years ago
Pls help! What's the answer?
Ivan

Answer:

The answer is b = 8a

Step-by-step explanation:

As, 0 x 8 = 0

2 1/2 = 5/2, 5/2 x 8 = 20

5 x 8 = 40

7 1/2 = 15/2, 15/2 x 8 = 60

10 x 8 = 80

13 1/2 = 27/2, 27/2 x 8 = 108

So all variables "a" when multiplied by 8 will give us the value in "b"

So b = 8a

4 0
2 years ago
Jack drove 150 miles in 3 hours. at that rate, how long will it taketo drive 400 miles
Tema [17]
150mi/3hrs = 50mph
400/50 = 8 hours
Check:
8hours * 50mi = 400 miles traveled

5 0
2 years ago
Read 2 more answers
PLEASE HELP WITH GRADE 11 MATH. Make sure you show the formula. Substitute values and show all mathematicall operations! show yo
Degger [83]

3x+y

x

​

 

=−3

=−y+3

​

The second equation is solved for xxx, so we can substitute the expression -y+3−y+3minus, y, plus, 3 in for xxx in the first equation:

\begin{aligned} 3\blueD{x}+y &= -3\\\\ 3(\blueD{-y+3})+y&=-3\\\\ -3y+9+y&=-3\\\\ -2y&=-12\\\\ y&=6 \end{aligned}

3x+y

3(−y+3)+y

−3y+9+y

−2y

y

​

 

=−3

=−3

=−3

=−12

=6

​

Plugging this value back into one of our original equations, say x = -y +3x=−y+3x, equals, minus, y, plus, 3, we solve for the other variable:

\begin{aligned} x &= -\blueD{y} +3\\\\ x&=-(\blueD{6})+3\\\\ x&=-3 \end{aligned}

x

x

x

​

 

=−y+3

=−(6)+3

=−3

​

The solution to the system of equations is x=-3x=−3x, equals, minus, 3, y=6y=6y, equals, 6.

We can check our work by plugging these numbers back into the original equations. Let's try 3x+y = -33x+y=−33, x, plus, y, equals, minus, 3.

\begin{aligned} 3x+y &= -3\\\\ 3(-3)+6&\stackrel ?=-3\\\\ -9+6&\stackrel ?=-3\\\\ -3&=-3 \end{aligned}

3x+y

3(−3)+6

−9+6

−3

​

 

=−3

=

?

−3

=

?

−3

=−3

​

Yes, our solution checks out.

Example 2

We're asked to solve this system of equations:

\begin{aligned} 7x+10y &= 36\\\\ -2x+y&=9 \end{aligned}

7x+10y

−2x+y

​

 

=36

=9

​

In order to use the substitution method, we'll need to solve for either xxx or yyy in one of the equations. Let's solve for yyy in the second equation:

\begin{aligned} -2x+y&=9 \\\\ y&=2x+9 \end{aligned}

−2x+y

y

​

 

=9

=2x+9

​

Now we can substitute the expression 2x+92x+92, x, plus, 9 in for yyy in the first equation of our system:

\begin{aligned} 7x+10\blueD{y} &= 36\\\\ 7x+10\blueD{(2x+9)}&=36\\\\ 7x+20x+90&=36\\\\ 27x+90&=36\\\\ 3x+10&=4\\\\ 3x&=-6\\\\ x&=-2 \end{aligned}

7x+10y

7x+10(2x+9)

7x+20x+90

27x+90

3x+10

3x

x

​

 

=36

=36

=36

=36

=4

=−6

=−2

​

Plugging this value back into one of our original equations, say y=2x+9y=2x+9y, equals, 2, x, plus, 9, we solve for the other variable:

\begin{aligned} y&=2\blueD{x}+9\\\\ y&=2\blueD{(-2)}+9\\\\ y&=-4+9 \\\\ y&=5 \end{aligned}

y

y

y

y

​

 

=2x+9

=2(−2)+9

=−4+9

=5

​

The solution to the system of equations is x=-2x=−2x, equals, minus, 2, y=5y=5y, equals, 5.

5 0
2 years ago
Help please and show work
vladimir1956 [14]

Answer: i think that jacks volume would be 24 i think jills is 882 i believe but i may be wrong

Step-by-step explanation:

8 0
2 years ago
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