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DochEvi [55]
3 years ago
15

Help me out the number inside the triangle is really throwing me off tbh

Mathematics
1 answer:
prisoha [69]3 years ago
6 0

We are given an angle of 60° and a side of 15 cm.

We are given the opposite and is looking for the hypotenuse so we will use the sine ratio to find x.

sin = opp/hyp

hyp = 15 / sin 60

hyp = 17.32...

//

We can also use the tangent ratio to find the adjecent and then use pythagorean to find x.

tan = opp/adj

adj = 15 / tan 60

adj = 8.660.....

8.660....² + 15² = 300²

since the square root of 300 is an irrational number, we have to turn it into a mixed radical.

The answer would be the top one.

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Plz help point is 50
meriva

Answer:

Your answer would be Phoenix. Phoenix had a temperature of 8 degrees.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Find the gain percent in the following:<br>Cost Price Rs 280,<br>(a) Selling Price<br>Rs 290​
Nikolay [14]

Answer:

3.57

Step-by-step explanation:

P=SP -CP

=290-280=10

P%=\frac{P*100}{CP}

=\frac{10*100}{280}

=\frac{1000}{280}

=3.57

4 0
3 years ago
H(x)=-x^2-4 and I(x)=2x+3<br> H(I(s))
ICE Princess25 [194]
Easy peasy
just subsitute I(x) for the x in the h(x) so
h(I(s))=-(2s+3)^2-4
distribute and simplify
h(I(s))=-(4s^2+12s+9)-4
h(I(s))=-4s^2-12s-9-4
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3 0
3 years ago
Equation<br> horizontal asymptote<br> vertical asymptote
ira [324]

Answer:

Hello,

In order to determine which is the horizontal asymptote remember that the horizontal is always x= something and remember that horizontal is straight from left to right.

So Horizontal asymptote = 2

For vertical asymptote it goes from the bottom of the graph, directly up. Think about it like this, you stand upright...or vertically right? So the vertical asymptote is

y= 0

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3 0
3 years ago
Use the given graph of f to state the value of each quantity, if it exists. (If an answer does not exist, enter DNE.)
alex41 [277]

Answer:

Hence the answer is given as follows,

Step-by-step explanation:

Graph of y = f(x) given,

(a) \lim_{x\rightarrow 2^{-}}f(x)=3

(b) \lim_{x\rightarrow 2^{+}}f(x)=1

(c) \lim_{x\rightarrow 2}f(x)= DNE \left \{ \therefore \lim_{x\rightarrow 2^{-}} f(x)\neq  \lim_{x\rightarrow 2^{+}}f(x) \right.

(d) f(2)=3

(e) \lim_{x\rightarrow 4}f(x) = 4

(f) f(4)= DNE.{ Hole in graph}

Hence solved.

3 0
3 years ago
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