Question

In a bag of 20 candies, 12 are red and 15 have peanuts in them. If the events of picking a red candy and picking a candy with peanuts are independent, how many of the red candies have peanuts?

Answer 1

Decision in the photo below

Answer 2

Answer:

9 red candies have peanuts.  

Step-by-step explanation:

Given:  

Total number of candies in the bag=20 candies,

Number of red candies = 12  

Number of candies with peanut = 15

To Find:

The number of red candies with peanut=?

Solution:

Since the picking a red candy and picking a candy with peanuts are independent

p(candies with Peanuts | red candies)=P(candies with Peanuts)

Hence

P(candies with Peanuts)=$\frac{15}{20}$

P(candies with Peanuts)=0.75

We Have 12 red candies, so

Number of red candies with peanuts=P(candies with Peanuts) x number of red candies

Number of red candies with peanuts=0.75 x 12

Number of red candies with peanuts= 9