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ruslelena [56]
3 years ago
11

2 copies of a code module are to be executed in parallel on identical processors organized into two communicating clusters A and

B. Cluster A contains 8 processors and cluster B contains 4 processors. How many sets of processors can be used if cluster A has 2 failed processors and cluster B has 4 failed processors?
Mathematics
1 answer:
swat323 years ago
3 0

Answer: There are 15 sets of processors.

Step-by-step explanation:

Since we have given that

Number of processors in cluster A = 8

Number of processors in cluster B = 4

Total processors = 12

Number of failed processors in cluster A = 2

Number of failed processors in cluster B = 4

Total failed processors = 2+4 = 6

So, Not failed processors = 12-6 = 6

Number of copies = 2

So, Number of sets of processors can be used is given by

^6C_2\\\\=15

Hence, there are 15 sets of processors.

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Answer:

Transformation include reflecting and dilating of points

The scale factor from PQR to P'Q'R' is 1/4

The coordinates of P"Q"R" are P"=(-1,0) Q"=(0,-1)  R"=(2,-1)           .

PQR and P′'Q′'R′' are not congruent

The points are given as:

p=(4,0)

q=(0,-4)

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(a)The scale factor from PQR to P'Q'R

To do this, we make use of corresponding sides QR and Q'R

So, the scale factor (k) is:

k=q'r'/qr

k=2/8

k=1/4

(b) The coordinates of P"Q"R from reflecting P'Q'R' about the y-axis

The rule of this transformation is:

(x,y)--------(-x,y)

So, we have:

p"=(-1,0)

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r"=(2,-1)

(c) Are triangle PQR and P"Q'R" congruent?

No they are not

This is so because

PQR was dilated by 1/4 to get P'Q'R

P'Q'R' and P"Q"R" are congruent

Hence,  PQR and P′'Q′'R′' are not congruent

Step-by-step explanation:

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