b) in the blood include monocytes and neutrophils.
which of what? is there an attachment
Answer:
I would say the correct answer is <u>A. 2 of subunit A, 4 of subunit B, and 2 of subunit C</u>
<u></u>
<u>Hope this help </u>
<u>I'm sorry if wrong </u>
<u>Have a nice day!!!</u>
The right answer is B.
The operator is the segment of DNA to which a chemical signal (a regulatory molecule) binds. It can be either a repressor signal or a transcription activating signal (DNA operator) or translation (RNA operator) of the genes of the operon.
In the case of loperon lactose, the operator is located downstream of the promoter so that it can regulate the trancription. In the case of this experiment, the promoter has been removed from the opterator, and in this case, can no longer regulate the transcription, and therefore the synthesis will be continuous (unregulated).
Another interesting fact is that beta galactosidase will not be transcribed since it will be positioned upstream of the promoter (so the E response is false).
Answer:
In hypertonic solution with high solute concentration than the plant cell that is about 1.0 M
Explanation:
The tonicity of the cell is determined by placing the cells in an either hypotonic, hypertonic or isotonic solution.
The plasmolysis refers to the process taking place in the plant cell which allows the movement of the water out of the cell through the process of osmosis which leads to the shrinkage of the cytoplasm.
The cytoplasm shrinks when the cell is placed in the hypertonic solution which contains a high amount of solute than the plant cell and therefore less amount of water.
As a result of this, the water moves out from the cell to the solution down their concentration gradient from high to a low level.
Thus, In hypertonic solution with high solute concentration than the plant cell that is about 1.0 M is the correct answer.
