It's B, Bowman's capsule !
Cl has nonmetallic properties
Phenotype is how the offspring will look like (the observable characteristics of it). the genotype is make up of the genes responsible for a trait
Answer:
A)
%
B)
%
Explanation:
A) Given
Frequency of individuals in the population having recessive phenotypes
%
Frequency of individuals in the population having recessive phenotypes is represented by ![q^2](https://tex.z-dn.net/?f=q%5E2)
![q^ 2 = 0.16\\q= \sqrt{0.16}\\ q = 0.4](https://tex.z-dn.net/?f=q%5E%202%20%3D%200.16%5C%5Cq%3D%20%5Csqrt%7B0.16%7D%5C%5C%20q%20%3D%200.4)
Thus frequency of recessive genes is equal to ![40%](https://tex.z-dn.net/?f=40%25)
frequency of dominant genes is equal to
![p = 1-q\\= 1-0.4\\= 0.6](https://tex.z-dn.net/?f=p%20%3D%201-q%5C%5C%3D%201-0.4%5C%5C%3D%200.6)
Now,
![p^2 + q^2+2pq = 1\\2pq = 1-0.16-0.36\\2pq = 0.48](https://tex.z-dn.net/?f=p%5E2%20%2B%20q%5E2%2B2pq%20%3D%201%5C%5C2pq%20%3D%201-0.16-0.36%5C%5C2pq%20%3D%200.48)
% of genes exist in the heterozygous condition
B.
Frequency of individuals in the population having recessive phenotypes
%
Frequency of individuals in the population having recessive phenotypes is represented by ![q^2](https://tex.z-dn.net/?f=q%5E2)
![q^ 2 = 0.01\\q= \sqrt{0.01}\\ q = 0.1](https://tex.z-dn.net/?f=q%5E%202%20%3D%200.01%5C%5Cq%3D%20%5Csqrt%7B0.01%7D%5C%5C%20q%20%3D%200.1)
Thus frequency of recessive genes is equal to ![10%](https://tex.z-dn.net/?f=10%25)
frequency of dominant genes is equal to
![p = 1-q\\= 1-0.1\\= 0.9](https://tex.z-dn.net/?f=p%20%3D%201-q%5C%5C%3D%201-0.1%5C%5C%3D%200.9)
Now,
![p^2 + q^2+2pq = 1\\2pq = 1-0.01-0.81\\2pq = 0.18](https://tex.z-dn.net/?f=p%5E2%20%2B%20q%5E2%2B2pq%20%3D%201%5C%5C2pq%20%3D%201-0.01-0.81%5C%5C2pq%20%3D%200.18)
% of genes exist in the heterozygous condition
Answer:
Population A has 4590 and population B has 1520 bacteria
Explanation:
Let’s mark bacteria:
a - bacteria from population A
b - bacteria from population B
Every bacteria <em>a</em> needs 4 units of the first nutrient and every bacteria <em>b</em> needs 1 unit of the same nutrient, so we can write it down as:
4*a + 1*b = 19880
Let’s do the same for the second nutrient. Every bacteria <em>a</em> needs 5 units of the second nutrient and every bacteria <em>b</em> needs 6 units of the second nutrient:
5*a + 6*b = 32070
Now there are two equations and two unknowns. From the first equation, we can separate <em>b</em>:
b = 19880 - 4a
Let’s place this <em>b</em> to the second equation:
5a + 6*(19880 - 4a) = 32070
5a + 119280 - 24a = 32070
119280 - 32070 = 24a - 5a
19a = 87210
a = 4590
This can be brought back to: b = 19880 - 4a
b = 1520