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Yuri [45]
3 years ago
13

A spinner divided into four equal parts, A, B, C, and D, is spun, then is followed by a roll of a standard six-sided die.

Mathematics
1 answer:
gavmur [86]3 years ago
6 0

Answer: 24

<u>Step-by-step explanation:</u>

Total Possible Outcomes given A, B, C, D  and 1, 2, 3, 4, 5, 6

= 4 x 6

= 24

*******************************************************************************

Answer: 3

<u>Step-by-step explanation:</u>

Total outcomes for an A and and odd number

= A and (1 or 3 or 5)

= 1 x 3

= 3

*******************************************************************************

Answer: \bold{\dfrac{1}{4,}\qquad \dfrac{1}{2,}\qquad \dfrac{1}{8}}

<u>Step-by-step explanation:</u>

Probability of an A out of A, B, C, D is: \dfrac{1}{4}

Probability of an odd (1, 3, 5) out of 1, 2, 3, 4, 5, 6 is: \dfrac{3}{6}=\dfrac{1}{2}

Probability of an A and an odd is: \dfrac{1}{4}\times\dfrac{1}{2}=\dfrac{1}{8}

*******************************************************************************

Answer: \bold{\dfrac{1}{2}}

<u>Step-by-step explanation:</u>

Probability of an odd (1, 3, 5) out of 1, 2, 3, 4, 5, 6 is: \dfrac{3}{6}=\dfrac{1}{2}

*******************************************************************************

Answer: \bold{\dfrac{3}{4}}

<u>Step-by-step explanation:</u>

Probability of an A or an odd is: \dfrac{1}{4}+\dfrac{1}{2}=\dfrac{1}{4}+\dfrac{2}{4}=\dfrac{3}{4}

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Halla la tasa de variación de cada funcion en el intervalo [-4,3] e indica si es positiva , negativa o nula A) f(x)=x2-2x+4 B) f
masya89 [10]

Answer:

A) \hspace{3}Rate\hspace{3}of\hspace{3}change=-5\hspace{3}Negative\\\\B)\hspace{3}Rate\hspace{3}of\hspace{3}change=-21\hspace{3}Negative  

Step-by-step explanation:

Given a function f(x), we called the rate of change to the number that represents the increase or decrease that the function experiences when increasing the independent variable from one value "x_1" to another "x_2".

The rate of change of f(x) between x_1 and x_2 can be calculated as follows:

Rate\hspace{3}of\hspace{3}change=f(x_2)-f(x_1)

For:

f(x)=x^2-2x+4

Let's find f(x_1) and f(x_2), where:

[x_1,x_2]=[-4,3]

f(x_1)=f(-4)=(-4)^2-2(4)+4=16-8+4=12\\f(x_2)=f(3)=(3)^2-2(3)+4=9-6+4=7

So:

Rate\hspace{3}of\hspace{3}change =7-12=-5\hspace{3}Negative

And for:

f(x)-3x+2

Let's find f(x_1) and f(x_2), where:

[x_1,x_2]=[-4,3]

f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7

So:

Rate\hspace{3}of\hspace{3}change =-7-14=-21\hspace{3}Negative

<em>Translation:</em>

Dada una función f(x), llamábamos tasa de variación al número que representa el aumento o disminución que experimenta la función al aumentar la variable independiente de un valor "x_1" a otro "x_2".

La tasa de variación de f(x) entre x_1 y x_2, puede ser calculada de la siguiente forma:

Tasa\hspace{3}de\hspace{3}variacion=f(x_2)-f(x_1)

Para:

f(x)=x^2-2x+4

Encontremos f(x_1) y f(x_2), donde:

[x_1,x_2]=[-4,3]

f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7

Entonces:

Tasa\hspace{3}de\hspace{3}variacion =7-12=-5\hspace{3}Negativa

Y para:

f(x)-3x+2

Encontremos f(x_1) y f(x_2), donde:

[x_1,x_2]=[-4,3]

f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7

Entonces:

Tasa\hspace{3}de\hspace{3}variacion=-7-14=-21\hspace{3}Negativa

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