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marishachu [46]

3 years ago

15

At Shaw's Market, apples cost $10 per case and bananas cost $6 per case. If an order comes in for a total of 300 cases for $2,00

0, what was the specific number of cases of apples? (Hint: Let A = cases of apples)

1 answer:

MissTica3 years ago

8 0

Come up with the two equations and solve simultaneously

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Mrs. Walker is instructing a team of students on designing the sailboat shown. Beth is working on the smaller sail, which is a r

Pachacha [2.7K]

Answer: OPTION C.

Step-by-step explanation:

1. To solve this problem you must apply the Pythagorean Theorem, which is shown below:

$a^{2}=b^{2}+c^{2}$

Where a is the hypotenuse, and b and c are the legs of the triangle.

2. When you solve for one of the legs and substitute values, you obtain that the result is:

$b=\sqrt{a^{2}-c^{2}}\\b=\sqrt{(24.8ft)^{2}-(8ft)^{2}}\\b=23.5ft$

5 0

3 years ago

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Find the value of x. PLEASE explain how you got your answer thanks!

Mnenie [13.5K]

Answer:

x = 96

Step-by-step explanation:

x + x - 5 + x - 11 + x - 8 = 360

4x - 24 = 360

4x = 360 + 24

4x = 384

x = 96

8 0

3 years ago

What is the product of -15 and -3

gayaneshka [121]

The product would be -18

6 0

3 years ago

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Solve the following using Substitution method<br> 2x – 5y = -13<br><br> 3x + 4y = 15

Digiron [165]

$\huge \boxed{\mathfrak{Question} \downarrow}$

Solve the following using Substitution method

2x – 5y = -13

3x + 4y = 15

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

$\left. \begin{array} { l } { 2 x - 5 y = - 13 } \\ { 3 x + 4 y = 15 } \end{array} \right.$

To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

$2x-5y=-13, \: 3x+4y=15$

Choose one of the equations and solve it for x by isolating x on the left-hand side of the equal sign. I'm choosing the 1st equation for now.

$2x-5y=-13$

Add 5y to both sides of the equation.

$2x=5y-13$

Divide both sides by 2.

$x=\frac{1}{2}\left(5y-13\right) \\$

Multiply $\frac{1}{2}\\$ times 5y - 13.

$x=\frac{5}{2}y-\frac{13}{2} \\$

Substitute $\frac{5y-13}{2}\\$ for x in the other equation, 3x + 4y = 15.

$3\left(\frac{5}{2}y-\frac{13}{2}\right)+4y=15 \\$

Multiply 3 times $\frac{5y-13}{2}\\$ .

$\frac{15}{2}y-\frac{39}{2}+4y=15 \\$

Add $\frac{15y}{2} \\$ to 4y.

$\frac{23}{2}y-\frac{39}{2}=15 \\$

Add $\frac{39}{2}\\$ to both sides of the equation.

$\frac{23}{2}y=\frac{69}{2} \\$

Divide both sides of the equation by 23/2, which is the same as multiplying both sides by the reciprocal of the fraction.

$\large \underline{ \underline{ \sf \: y=3 }}$

Substitute 3 for y in $x=\frac{5}{2}y-\frac{13}{2}\\$ . Because the resulting equation contains only one variable, you can solve for x directly.

$x=\frac{5}{2}\times 3-\frac{13}{2} \\$

Multiply 5/2 times 3.

$x=\frac{15-13}{2} \\$

Add $-\frac{13}{2}\\$ to $\frac{15}{2}\\$ by finding a common denominator and adding the numerators. Then reduce the fraction to its lowest terms if possible.

$\large\underline{ \underline{ \sf \: x=1 }}$

The system is now solved. The value of x & y will be 1 & 3 respectively.

$\huge\boxed{ \boxed{\bf \: x=1, \: y=3 }}$

8 0

2 years ago

PLZ HELP ITS DUE TODAY!!!!

coldgirl [10]

Answer:

2.69827 × 10⁹

Step-by-step explanation:

any questions?

7 0

2 years ago