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Ugo [173]
4 years ago
6

Jack wants to find out which can of pineapples is the best buy. He has a choice of four

Mathematics
2 answers:
Juliette [100K]4 years ago
5 0
6 maybe but I can’t remember but I took this tho
ryzh [129]4 years ago
5 0

Answer:

Its 6 i took the test already

Step-by-step explanation:

hahahahha bro online school lowkey fye

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This questionn please
nasty-shy [4]
Let X be the total number of guests
\frac{1}{3} x + \frac{5x}{12} + 23 \\ \frac{12x + 15x + 828}{36} \\ \frac{17x + 828}{36}
when X =1
(17+828)/36
845/36=23.5
am sorry but the question is not that clear
pls mark as brainliest
8 0
3 years ago
Help me plz due today​
kirill115 [55]

Answer:

The coefficients are 4 and 2

Step-by-step explanation:

they are the ones in front of the variables

for example, the coefficient of 12x is 12

anyways, stan tokoroki for clear skin

6 0
3 years ago
Patty is ordering vests for her scout troop to wear in the Veterans Day parade. She ordered 12 vests from the Festive Features c
anygoal [31]

Answer:

Step-by-step explanation:

7 0
3 years ago
A simple random sample from a population with a normal distribution of 98 body temperatures has x =98.90 °F and s =0.68°F. Const
Ludmilka [50]

Answer:

0.609 \leq \sigma \leq 0.772  

And the best conclusion would be:

D. This conclusion is safe because 1.40 °F is outside the confidence interval.

Step-by-step explanation:

1) Data given and notation  

s=0.68 represent the sample standard deviation  

\bar x =98.90 represent the sample mean  

n=98 the sample size  

Confidence=90% or 0.90  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .  

2) Calculating the confidence interval  

The confidence interval for the population variance is given by the following formula:  

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}  

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:  

df=n-1=98-1=97  

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.05,97)" "=CHISQ.INV(0.95,97)". so for this case the critical values are:  

\chi^2_{\alpha/2}=120.990  

\chi^2_{1- \alpha/2}=75.282  

And replacing into the formula for the interval we got:  

\frac{(97)(0.68)^2}{120.990} \leq \sigma \leq \frac{(97)(0.68)^2}{75.282}  

0.371 \leq \sigma^2 \leq 0.596  

Now we just take square root on both sides of the interval and we got:  

0.609 \leq \sigma \leq 0.772  

And the best conclusion would be:

D. This conclusion is safe because 1.40 °F is outside the confidence interval.

3 0
3 years ago
What is the difference between 2.23 seconds and 3.13 seconds?
boyakko [2]

Answer:

0.9

Step-by-step explanation:

3.13-2.23=0.9

7 0
3 years ago
Read 2 more answers
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