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rosijanka [135]
2 years ago
9

Whats 5 plus 39 minus 44​

Mathematics
2 answers:
ipn [44]2 years ago
5 0

Answer:

The correct answer is 0.

Step-by-step explanation:

5 + 39 = 44

44 - 44 = 0

Hope this helps,

♥<em>A.W.E.</em><u><em>S.W.A.N.</em></u>♥

yaroslaw [1]2 years ago
4 0

Answer:

0

Step-by-step explanation:

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ahrayia [7]

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11h+12

Step-by-step explanation:

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2 years ago
For question 3, is it right though? Thankss
pishuonlain [190]

Yes it is correct, 7/12 is the equivalent to C. 7 divided by 12

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The most common form of color blindness is an inability to distinguish red from green. However, this particular form of color bl
Alecsey [184]

Answer:

(a) The correct answer is P (CBM) = 0.79.

(b) The probability of selecting an American female who is not red-green color-blind is 0.996.

(c) The probability that neither are red-green color-blind is 0.9263.

(d) The probability that at least one of them is red-green color-blind is 0.0737.

Step-by-step explanation:

The variables CBM and CBW are denoted as the events that an American man or an American woman is colorblind, respectively.

It is provided that 79% of men and 0.4% of women are colorblind, i.e.

P (CBM) = 0.79

P (CBW) = 0.004

(a)

The probability of selecting an American male who is red-green color-blind is, 0.79.

Thus, the correct answer is P (CBM) = 0.79.

(b)

The probability of the complement of an event is the probability of that event not happening.

Then,

P(not CBW) = 1 - P(CBW)

                   = 1 - 0.004

                   = 0.996.

Thus, the probability of selecting an American female who is not red-green color-blind is 0.996.

(c)

The probability the woman is not colorblind is 0.996.

The probability that the man is  not color- blind is,

P(not CBM) = 1 - P(CBM)

                   = 1 - 0.004  

                   = 0.93.

The man and woman are selected independently.

Compute the probability that neither are red-green color-blind as follows:

P(\text{Neither is Colorblind}) = P(\text{not CBM}) \times  P(\text{not CBW})\\ = 0.93 \times  0.996 \\= 0.92628\\\approx 0.9263

Thus, the probability that neither are red-green color-blind is 0.9263.

(d)

It is provided that a one man and one woman are selected at random.

The event that “At least one is colorblind” is the complement of part (d) that “Neither is  Colorblind.”

Compute the probability that at least one of them is red-green color-blind as follows:

P (\text{At least one is Colorblind}) = 1 - P (\text{Neither is Colorblind})\\ = 1 - 0.9263 \\= 0.0737

Thus, the probability that at least one of them is red-green color-blind is 0.0737.

6 0
3 years ago
Gallup conducted a survey from April 1 to 25, 2010, to determine the congressional vote preference of the American voters.15 The
Lisa [10]

Answer:

p ( x > 2746 ) = p ( z > - 1.4552 )

                      = 1 - 0.072806

                      = 0.9272

This shows that there is > 92% of a republican candidate winning the election hence I will advice Gallup to declare the Republican candidate winner

Step-by-step explanation:

Given data:

51% of male voters preferred a Republican candidate

sample size = 5490

To win the vote one needs ≈ 2746 votes

In order to advice Gallup appropriately lets consider this as a binomial distribution

n = 5490

p = 0.51

q = 1 - 0.51 = 0.49

Hence n_{p} > 5  while n_{q}  < 5

we will consider it as a normal distribution

From the question :

number of male voters who prefer republican candidate  ( mean ) ( u )

= 0.51 * 5490 = 2799.9

std = \sqrt{npq} = \sqrt{5490 * 0.51 *0.49} = 37.0399  ---- ( 1 )

determine the Z-score = (x - u ) / std  ---- ( 2 )

x = 2746 , u = 2799.9 , std = 37.0399

hence Z - score = - 1.4552

hence

p ( x > 2746 ) = p ( z > - 1.4552 )

                      = 1 - 0.072806

                      = 0.9272

This shows that there is > 92% of a republican candidate winning the election hence I will advice Gallup to declare the Republican candidate winner

7 0
2 years ago
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