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DochEvi [55]
3 years ago
9

On a coordinate grid, a park is located at (3,0) and the pool is located at (-3,3). If the tennis courts are the midpoint betwee

n the park and the pool, what is the approximate distance from the pool to the tennis courts? (Note: 1 unit equals 1 mile)
A) 1.5 miles
B) 2.79 miles
C) 3.35 miles
D) 4.74 miles
Mathematics
2 answers:
Lemur [1.5K]3 years ago
7 0

I think c if not sorry have a good day

nadezda [96]3 years ago
7 0
<h2>Answer:</h2>

The approximate distance from the pool to the tennis courts is:

                    C)  3.35 miles

<h2>Step-by-step explanation:</h2>

It is given that:

On a coordinate grid, a park is located at (3,0) ande the pool is located at (-3,3).

The tennis courts are the midpoint between the park and the pool.

This means that the distance from the pool to the tennis court is half the distance between the pool and the park.

The distance between pool and park is calculated by using the distance formula as follows:

Distance\ between\ pool\ and\ park=\sqrt{(3-(-3))^2+(0-3)^2}\\\\Distance\ between\ pool\ and\ park=\sqrt{(3+3)^2+(-3)^2}\\\\i.e.\\\\Distance\ between\ pool\ and\ park=\sqrt{6^2+3^2}\\\\i.e.\\\\Distance\ between\ pool\ and\ park=\sqrt{36+9}\\\\i.e.\\\\Distance\ between\ pool\ and\ park=\sqrt{45}\\\\i.e.\\\\Distance\ between\ pool\ and\ park=3\sqrt{5}\\\\i.e.\\\\Distance\ between\ pool\ and\ park=6.7082\ units

Hence,

Distance\ from\ pool\ to\ tennis\ court=\dfrac{6.7082}{2}\\\\i.e.\\\\Distance\ from\ pool\ to\ tennis\ court=3.3541\ units

Now, it is given that:

   1 unit= 1 mile

Hence, 3.3541 unit=3.3541 miles.

Hence, the answer is: Option: C

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