Answer: Explanation:
It is a two-step process that reduces the chromosome number by half—from 46 to 23—to form sperm and egg cells. When the sperm and egg cells unite at conception, each contributes 23 chromosomes so the resulting embryo will have the usual 46.
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If there was a dramatic increase in skeletal muscle cell damage and apoptosis, I would not expect a change in blood myoglobin and CK levels, because these markers are linked to cardiac muscle damage.
<h3>What does high CK-MB mean?</h3>
Elevated CKMB can be a sign of cardiac (heart muscle) damage or chronic kidney failure. At the onset of acute symptoms, after cardiac peaks, CKMB values are elevated after 3-6 peaks after 12-24 hours between 12-24 hours, values at 24-48-48.
With this information, we can conclude that if there was a dramatic increase in skeletal muscle cell damage and apoptosis, we would not expect a change in blood myoglobin and CK levels, because these markers are linked to cardiac muscle damage.
Learn more about myoglobin in brainly.com/question/8111632
Answer: The following statements <em>comparing respiration in fish and in mammals</em> is correct:
- The movement of the respiratory medium in mammals is bidirectional, but in fish it is unidirectional.
Explanation:
<u>Breathing </u>is the process by which living beings <em>exchange gases</em> with the external environment. It consists of the <u>entry of oxygen</u> into the body of a living being and the <u>exit of carbon dioxide</u> from it .
Active ventilation occurs if the animal produces the currents (of air or water) that flow to and from its respiratory membranes. It can be :
- Unidirectional. (air or water is pumped onto the respiratory membrane in only one direction).
- Bidirectional. (air or water is transported to the respiratory membrane and moves away from it through the same route like in the mammals).
Biology is the study (2) of life (1)
Answer:
The fraction of the offspring that will show the phenotype produced by the recessive c allele is 1024/4096 = 0.25 A-BbccDdE-Ff = 25%
Explanation:
You can calculate the fraction of the offspring that will show the phenotype produced by the recessive c allele by making the punnet square for each gene and then multipling the phenotypic proportions, like this:
Cross) AAbbCcDDEeff x AaBBCcddEEFF
Cross For each gene by separately:
Gametes) A A A a
F1) 2/4 AA
2/4 Aa
Gametes) b b B b
F1) 4/4 Bb
Gametes) C c C c
F1) 1/4 CC
2/4 Cc
1/4 cc
Gametes) D D d d
F1) 4/4 Dd
Gametes) E e E E
F1) 2/4 Ee
2/4 EE
Gametes) f f F F
F1) 4/4 Ff
So, fraction of the offspring that will show the phenotype produced by the recessive c allele is:
4/4 A- x 4/4 Bb x 1/4 cc x 4/4 Dd x 4/4 E- x 4/4 Ff =
1024/4096 = 0.25 A-BbccDdE-Ff =25%
