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jarptica [38.1K]
3 years ago
7

Determine whether the two angles in each figure are complementary, supplementary, or neither.

Mathematics
2 answers:
-BARSIC- [3]3 years ago
8 0
1. neither
2. supplementary
3. neither
4. complementary
snow_tiger [21]3 years ago
7 0
1.linear pair
2. neither
3. vertical
4. neither
5. vertical
6. neither
7. linear pair
8. neither

Their starting from up to down not side to side
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Which choices are equivalent to the fraction below check all the apply ""24" over 30
user100 [1]

Answer:

c) The reduced form of the given fraction   \frac{24}{30} =  \frac{4}{5}

Step-by-step explanation:

Here, the given expression is  "24 over 30".

The given expression is  is equivalent to \frac{24}{30}

Now by Prime Factorization:

24  =  2 x 2 x 2 x 3

30  = 2 x 3 x 5

⇒ The common factors in 24 and 30 is  2 x 3  = 6

So, \frac{24}{30}  = \frac{2 \times 2 \times 2 \times 2 \times 3}{2 \times 3 \times 5}   = \frac{6 \times 4}{6 \times 5}   = \frac{4}{5}

Hence the reduced form of the given fraction   \frac{24}{30} =  \frac{4}{5}

6 0
3 years ago
Math Plz Help. <br><br>Please graph with two points! <br>explain how you found your answer
Softa [21]
X intercept: y = 0
y= -3/4x -4
0 = -3/4 x - 4
4= -3/4 x
4 • -4/3 = x
-5.3 = x
y intercept: x = 0
y = -3/4 x -4
y = -3/4 (0) -4
y = -4
the points are (-5.3, 0) and (0, -4)
3 0
3 years ago
Show that in any group of 101 people there are at least two persons having the same number friends (It is assumed that if a pers
vladimir1956 [14]

Answer:

Step-by-step explanation:

Let us assume that if possible in the group of 101, each had a different number of friends.  Then the no of friends 101 persons have 0,1,2,....100 only since number of friends are integers and non negative.

Say P has 100 friends then P has all other persons as friends.  In this case, there cannot be any one who has 0 friend.  So a contradiction.  Hence proved

Part ii: EVen if instead of 101, say n people are there same proof follows as

if different number of friends then they would be 0,1,2...n-1

If one person has n-1 friends then there cannot be any one who does not have any friend.

Thus same proof follows.

7 0
3 years ago
What is 45% out of 44209
Talja [164]

Answer:

1.01789228E-5

Step-by-step explanation:

hope this helped :)

3 0
3 years ago
Read 2 more answers
Find the sum of the geometric series 512+256+ . . .+4
mario62 [17]

\bf 512~~,~~\stackrel{512\cdot \frac{1}{2}}{256}~~,~~...4

so, as you can see above, the common ratio r = 1/2, now, what term is +4 anyway?

\bf n^{th}\textit{ term of a geometric sequence}\\\\a_n=a_1\cdot r^{n-1}\qquad \begin{cases}n=n^{th}\ term\\a_1=\textit{first term's value}\\r=\textit{common ratio}\\----------\\r=\frac{1}{2}\\a_1=512\\a_n=+4\end{cases}

\bf 4=512\left( \cfrac{1}{2} \right)^{n-1}\implies \cfrac{4}{512}=\left( \cfrac{1}{2} \right)^{n-1}\\\\\\\cfrac{1}{128}=\left( \cfrac{1}{2} \right)^{n-1}\implies \cfrac{1}{2^7}=\left( \cfrac{1}{2} \right)^{n-1}\implies 2^{-7}=\left( 2^{-1}\right)^{n-1}\\\\\\(2^{-1})^7=(2^{-1})^{n-1}\implies 7=n-1\implies \boxed{8=n}

so is the 8th term, then, let's find the Sum of the first 8 terms.

\bf \qquad \qquad \textit{sum of a finite geometric sequence}\\\\S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad \begin{cases}n=n^{th}\ term\\a_1=\textit{first term's value}\\r=\textit{common ratio}\\----------\\r=\frac{1}{2}\\a_1=512\\n=8\end{cases}

\bf S_8=512\left[ \cfrac{1-\left( \frac{1}{2} \right)^8}{1-\frac{1}{2}} \right]\implies S_8=512\left(\cfrac{1-\frac{1}{256}}{\frac{1}{2}}  \right)\implies S_8=512\left(\cfrac{\frac{255}{256}}{\frac{1}{2}}  \right)\\\\\\S_8=512\cdot \cfrac{255}{128}\implies S_8=1020

7 0
3 years ago
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