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kherson [118]
4 years ago
6

Help me help me help me help me simplify (9x8y3)1/2

Mathematics
1 answer:
igor_vitrenko [27]4 years ago
5 0
4\frac{1}{2}x4y1.5
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The perimeter of a rectangle is 90 cm the length is 27 cm what is the width of the rectangle
ser-zykov [4K]

Answer:

width = 18 cm

Step-by-step explanation:

perimeter of rectangle = 2(length + width)

then:

90 = 2(27+w)

90/2 = 27+w

w = width

45 = 27+w

45 - 27 = w

18 = w

Check:

90 = 2(27+18)

90 =2*45                                       =

3 0
3 years ago
50(1.05)t < 100 how much growth or decay
makvit [3.9K]
50(1.05)t \ \textless \  100

3 0
3 years ago
The average Act score follows a normal distribution, with a mean of 21.1 and a standard deviation of 5.1. What is the probabilit
ohaa [14]

Answer:

0.43% probability that the mean IQ score of 50 randomly selected people will be more than 23

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question:

\mu = 21.1, \sigma = 5.1, n = 50, s = \frac{5.1}{\sqrt{50}} = 0.7212

What is the probability that the mean IQ score of 50 randomly selected people will be more than 23

This is 1 subtracted by the pvalue of Z when X = 23. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{23 - 21.1}{0.7212}

Z = 2.63

Z = 2.63 has a pvalue of 0.9957

1 - 0.9957 = 0.0043

0.43% probability that the mean IQ score of 50 randomly selected people will be more than 23

5 0
3 years ago
A space shuttle travels at 2.6 x 10,000 feet per second. An hour is 3.6 x 1,000 seconds. This expression can be used to find the
guapka [62]

Answer:

7.22 feet

Step-by-step explanation:

From the question,

s = d/t................. Equation 1

Where s = speed of the space shuttle, d = distance traveled by the shuttle in an hour, t = time taken to travel the distance

make d the subject of the equation,

d = s×t.................... Equation 2

Given: s = 2.6×10000 feet per seconds, t = 1 hour =  3.6×1000 seconds.

Substitute these values into equation 2

d = (2.6×10000)/(3.6×1000)

d = 26000/3600

d = 7.22 feet.

Hence the shuttle travels 7.22 feet in an hour

6 0
3 years ago
Simon caught 5 striped fish. Each one weighed the same number of pounds.Then he caught another fish that weighted 7 pounds. Writ
nekit [7.7K]
5x + 7 

5x represents the weight of the 5 striped fish. 

7 represents the fish that weighs 7 pounds. 
8 0
4 years ago
Read 2 more answers
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