Subtract 10 and divide by 7
The standard form of the quadratic function f(x) = -3x^2 + 6x - 2 is f(x) = -3x^2 + 6x - 2
<h3>How to represent the
quadratic function in standard form?</h3>
The quadratic function is given as
f(x) = -3x^2 + 6x - 2
The standard form of a quadratic function is represented as:
f(x) = ax^2 + bx + c
When both equations are compared, we can see that the function f(x) = -3x^2 + 6x - 2 is already in standard form
Where
a = -3
b = 6
c = -2
Hence, the standard form of the quadratic function f(x) = -3x^2 + 6x - 2 is f(x) = -3x^2 + 6x - 2
Read more about quadratic function at
brainly.com/question/25841119
#SPJ1
Answer:
k = 2
Step-by-step explanation:
subtract 9 from both sides and you have 3k=6
then divide by three on both sides to get 2
If n is an integer, then cos(n(2<span>π))=1.
Take n=0, cos(2</span>π)=cos(0)=1, n=1, cos(2π)=1, n=2, cos(2(2π))=cos(4<span>π)=cos(0)=1...
If n is not an integer, well, ..... we don't know the value, which depends on the value of n.</span>
The greatest common factor of 11m^3 and 13m^2 is m^2. 11 and 13 don't really have a greatest common factor (they're both prime numbers), and m^2 goes into each of them.
