Given:
The width of a kitchen is 4.2 metres.
Kitchen cupboard widths are 60 cm.
To find:
The number of kitchen cupboard that will fit in 4.2 metres.
Solution:
Let x be the number of kitchen cupboard that will fit in 4.2 metres.
Width of 1 cupboard = 60 cm
Width of x cupboards = 60x cm
We know that, 1 m = 100 cm.
Width of a kitchen = 4.2 metres
= 4.2×100 cm
= 420 cm
Now, the width of the x cupboards is equal to width of the kitchen.
Therefore, the number of kitchen cupboard that will fit in 4.2 metres is 7.
Answer:
Here is the graph of y is a function of x.
Answer:
150.833... or 150 and 5/6 crates
Step-by-step explanation:
We can create an equation to solve this.
Let x represent the number of 120 kilogram crates that can be loaded into the chipping container.
120x (weight of the crates) + 5900 (weight already in the container) = 24000 (max weight in the container)
We'll start by subtracting 5900 from both sides to try to isolate x, the number of containers we still need to meet 24000 kilograms.
120x = 18100
Now we just have to isolate x by dividing by 120.
x = 150.83333333333333333333333333333
If you want to use a mixed fraction form for this solution since the 3's keep repeating, it would be 150 and 5/6 crates.
Answer:
the probability that all tomatoes are sold is 0.919 (91.9%)
Step-by-step explanation:
since the random variable X= number of tomatoes that are demanded, is normally distributed we can make the standard random variable Z such that:
Z=(X-μ)/σ = (83 - 125)/30 = -1.4
where μ= expected value of X= mean of X (since X is normally distributed) , σ=standard deviation of X
then all tomatoes are sold if the demand surpasses 83 tomatos , therefore
P(X>83) = P(Z>-1.4) = 1- P(Z≤-1.4)
from tables of standard normal distribution →P(Z≤-1.4)=0.081 , therefore
P(X>83) = 1- P(Z≤-1.4) = 1 - 0.081 = 0.919 (91.9%)
thus the probability that all tomatoes are sold is 0.919 (91.9%)
