because y^3 is raised to the power of two, we will have to multiply the exponents rather than adding them.
By distributing the power of 2, we will get y^2(6).
Because now the exponents are being multiplied, we can just add them to get y^8. The other y has a power of 1, so we'll just add the power of that y as well to get y^9.
summary:
multiply exponents if they are being raised to a power.
add exponents if they are being multiplied, and only add them if they have the same base (in this case, both the bases of the exponents are y, so we can add them)
Answer: 3
Step-by-step explanation:
You can answer this question by using the equation
(8+x)(7+x)=110
The x represents the width, as we do not know the area. If you simplify the equation, it becomes 56+15x+x2=110.
If you move all the terms to the left side, and rearrange it, it can become x^2+15x-54=0
This can be simplified into (x-3)(x+18)=0
This equation makes it so that x is either 3 or -18. It is not possible for a width to be -18, so the width must be 3.
Step 1. Simplify
to
Step 2. Simplify
to
Step 3. Simplify
to
Step 4. Cancel
on both sides
Step 5. Multiply both sides by
(the LCM of
)
Step 6. Expand
Step 7. Subtract
from both sides
Step 8. Simplify
to
Step 9. Multiply both sides by
Done! :) Hope this helps! :)
Answer:
selecting one item? If you mean each color:
40% chance for a red marble / 2/5 chance
60% chance for a blue marble / 3/5 chance
Step-by-step explanation:
Because there are 12 blue marbles and 8 red marbles, we would total them to see how many marbles there are in total. There are 20 in total, but to find the probability, if we put all 20 marbles in a bag (blue and red), and we picked a marble at random, there are 8 red marbles and 12 blue marble in that bag. The probability that I will choose red marbles is 8/20 (or 8 red marbles out of 20 total marbles), and for blue marbles, it would be 12/20 (or 12 blue marbles out of 20 total marbles). Simplify both expression to 2/5, and 3/5 respectively. Finally, if you need percentage, just multiply the denominator by 5 to get it to a hundred, and do the same to the numerator. This way you don't change the value of the expression.
