Answer:
0.229 M/s is molecular nitrogen reacting
Explanation:

Rate of the reaction :
![R=-\frac{1}{1}\frac{d[N_2]}{dt}=-\frac{1}{3}\frac{d[H_2]}{dt}=\frac{1}{2}\frac{d[NH_3]}{dt}](https://tex.z-dn.net/?f=R%3D-%5Cfrac%7B1%7D%7B1%7D%5Cfrac%7Bd%5BN_2%5D%7D%7Bdt%7D%3D-%5Cfrac%7B1%7D%7B3%7D%5Cfrac%7Bd%5BH_2%5D%7D%7Bdt%7D%3D%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7Bd%5BNH_3%5D%7D%7Bdt%7D)
Rate at which hydrogen gas is reaction :
![\frac{d[H_2]}{dt}=0.0687 M/s](https://tex.z-dn.net/?f=%5Cfrac%7Bd%5BH_2%5D%7D%7Bdt%7D%3D0.0687%20M%2Fs)
Rate at which hydrogen gas is reaction :
![\frac{d[N_2]}{dt}=?](https://tex.z-dn.net/?f=%5Cfrac%7Bd%5BN_2%5D%7D%7Bdt%7D%3D%3F)
![-\frac{1}{1}\frac{d[N_2]}{dt}=-\frac{1}{3}\frac{d[H_2]}{dt}](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B1%7D%5Cfrac%7Bd%5BN_2%5D%7D%7Bdt%7D%3D-%5Cfrac%7B1%7D%7B3%7D%5Cfrac%7Bd%5BH_2%5D%7D%7Bdt%7D)
![\frac{d[N_2]}{dt}=\frac{1}{3}\times 0.0687 M/s](https://tex.z-dn.net/?f=%5Cfrac%7Bd%5BN_2%5D%7D%7Bdt%7D%3D%5Cfrac%7B1%7D%7B3%7D%5Ctimes%200.0687%20M%2Fs)

0.229 M/s is molecular nitrogen reacting
Answer:
the correctanswer is a a and b
From a stock solution of 3.00 m nitric acid, 9.391 ml of stock solution is needed to create a 0.161 m nitric acid solution, which has a total volume of 175 ml of the diluted solution.
A chemical reagent is present in vast quantities as a stock solution. It has a uniform concentration. Examples of typical stock solutions in laboratories are nitric acid and hydrochloric acid. These play a critical role in creating the titration-related solution preparations.
We know the formula for dilution type problems
M1 VI = M2 V 2
Where,
M, = initial molarity
V , = initial Volume
M2 = final molarity
V 2 = final Volume
Hene given -
M, = 3.00 M
VI = ?
M2 = 0.161M
V 2 = 175 ml
Accordingly ' MI V1 = M2 V 2
V1 =
V1= (0.161M*175ml)/ 3.00M
v1 = 9.391
The required volume of Stock solution is 9.391ml.
Learn more about Stock solution here
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Are carried on chromosomes.
Not sure about the "determined traits", but genes do determine many traits in the organism.
We know that Zinc (Zn) has a molar mass of 65.39
g/mol. Hence the remaining is:
136.28 - 65.39=70.89
While molar mass of Chlorine (Cl) is 35.453 g/mol .
70.89 / 35.453 =2 => Cl
<span>So the formula is ZnCl2</span>