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klio [65]
3 years ago
7

How is the combined gas law modified to form the ideal gas law?

Chemistry
1 answer:
Setler79 [48]3 years ago
4 0
The answer is A) each side of the equations is divided by the number of moles. 
The combined gas law equation
     P1V1/T1 = P2V2/T2
becomes
     P1V1/n1T1 = P2V2/n2T2
with the addition of Avogadro's law relating volume and number of moles of a gas.This modification is when the number of moles of gas in a sample is allowed to change in addition to pressure, temperature and volume. This also means that pressure multiplied by the volume and divided by the product of the number of moles and temperature is a constant:
     PV/nT = constant
which if written in the form PV = nRT is the ideal gas law equation where R is the gas constant.
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From the addition of water to the molecule of an alkene is obtained a product containing 21.6% O2. Write the addition reaction.
klemol [59]

Addition reaction between water molecules and alkene molecules produces alcohol.

<h3>What is addition reaction?</h3>

Addition reaction generally takes place across the unsaturated carbon compounds.

When water molecule (H₂O) is added to the alkene which may be ethene (C₂H₄) molecule then formation of product i.e. ethanol (CH₃CH₂OH) takes place through the addition of hydrogen and hydroxyl group across the double bond. And reaction is shown in the attached image.

Hence formation of alcohol product takes place.

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3 0
2 years ago
33 grams of NH4NO3 will produce how many grams of water
Leni [432]

Answer:

66 grams

Explanation:

For every 1 gram of NH4NO3 equals 2 grams of water

8 0
4 years ago
Measuring how quickly a reactant disappears is one way to measure the ______________of the reaction
LUCKY_DIMON [66]

Explanation:

More quickly a reactant will disappear, the more quickly it will result in the formation of products. This means that consumption or disappearance of reactants determines the rate of a reaction because only then products will be formed.

Thus, we can conclude that measuring how quickly a reactant disappears is one way to measure the rate of the reaction.

5 0
4 years ago
Read 2 more answers
How many more neutrons would be in an isotope of sulfur-31 than a normal sulfur atom?
telo118 [61]

As sulfur-31 has 16 protons (equivalent to the atomic number) in total. The quantity of protons and electrons in an atom is equal. Consequently, sulfur-31 has 16 electrons in total.

As a result, sulfur-31 has (31-16) or 15 neutrons (the difference between the mass number and atomic number).

What is the atomic number?

The average mass of an element's atoms expressed in atomic mass units is known as its atomic mass (amu, also known as daltons, D).

  • The mass of each isotope is multiplied by its abundance to produce the atomic mass, which is a weighted average of all the isotopes of that element.
  • (Atomic mass is also known as atomic weight however, "mass" is a more precise phrase.)

The atomic mass of an element, measured in AMU, is equal to the mass in grams of one mole of an element.

  • This relationship between the atomic mass and the mole concept is important in chemistry.

Hence, the answer is 15neutrons.

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8 0
2 years ago
What is the percent composition of NaHCO3?
zhuklara [117]

Answer:

                Option-C (27.36% Na, 1.20% H, 14.30% C, and 57.14% O)

Explanation:

<em>Percent Composition</em> is defined as the <u><em>%age by mass of each element present in a compound</em></u>. Therefore, it is a relative amount of each element present in a compound.

Calculating Percent Composition of NaHCO₃:

1: Calculating Molar Masses of all elements present in NaHCO₃:

              a) Na  =  22.99 g/mol

             b) H  =  1.01 g/mol

              c) C  =  12.01 g/mol

              d) O₃  =  16.0 × 3 =  48 g/mol

2: Calculating Molecular Mass of NaHCO₃:

              Na  =  22.99 g/mol

             H    =  1.01 g/mol

              C    =  12.01 g/mol

              O₃  =  48 g/mol

                       ----------------------------------  

Total                  84.01 g/mol

3: Divide each element's molar mass by molar mass of NaHCO₃ and multiply it by 100:

For Na:

                 =  22.99 g.mol⁻¹ ÷ 84.01 g.mol⁻¹ × 100

                 =  27.36 %

For H:

                 =  1.01 g.mol⁻¹ ÷ 84.01 g.mol⁻¹ × 100

                 =  1.20 %

For C:

                 =  12.01 g.mol⁻¹ ÷ 84.01 g.mol⁻¹ × 100

                 =  14.29 % ≈ 14.30 %

For O:

                 =  48.0 g.mol⁻¹ ÷ 84.01 g.mol⁻¹ × 100

                 =  57.13 % ≈ 57.14 %

8 0
3 years ago
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