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klio [65]
3 years ago
7

How is the combined gas law modified to form the ideal gas law?

Chemistry
1 answer:
Setler79 [48]3 years ago
4 0
The answer is A) each side of the equations is divided by the number of moles. 
The combined gas law equation
     P1V1/T1 = P2V2/T2
becomes
     P1V1/n1T1 = P2V2/n2T2
with the addition of Avogadro's law relating volume and number of moles of a gas.This modification is when the number of moles of gas in a sample is allowed to change in addition to pressure, temperature and volume. This also means that pressure multiplied by the volume and divided by the product of the number of moles and temperature is a constant:
     PV/nT = constant
which if written in the form PV = nRT is the ideal gas law equation where R is the gas constant.
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ArbitrLikvidat [17]

Answer:

Option B

Explanation:

Magnesium is an alkali earth metal and chlorine is a nonmetal. Due to this, and their differences in electronegativity, the elements form an ionic bond. Since magnesium has two valence electrons, it will give them up to two chlorine atoms (which has 7 valence electrons), which needs them to complete its octet. From this, magnesium forms a cation, and will have the ion formula Mg(2+). The two chlorine atoms form anions, and will have the ion formula Cl(1-).

Terms:

  • Cation: a positively charged ion
  • Anion: a negatively charge ion.
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7 0
3 years ago
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DanielleElmas [232]
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3 years ago
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Naoki's bicycle has a mass of 10 kg. If Naoki sits on her bicycle and starts pedaling with a force of 168 N, causing an accelera
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Answer:

50 kg

Explanation:

Data:

Mass of bicycle = 10 kg

                       F = 168 N

                       a = 2.8 m/s²

Calculation:

                     F = ma     Divide each side by m, Then

                 m = F/a

                     = 168/2.8

                      = 60 kg

                 m = mass of bicycle + Naoki's mass. Then

                60 = 10 + Naoki's mass     Subtract 10 from each side

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3 years ago
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Answer:

The work done and heat absorbed are both -8,1 kJ

Explanation:

The work done in an isobaric process is defined as:

W = -P (Vf - Vi)

Where P is pressure ( 10 atm)

Vf = 10 L

Vi = 2 L

Thus, <em>W = -80 atm×L ≡ -8,1 kJ</em>

This is the work done in expansion of the gas.  As the gas remains at the same temperature, there is no change in internal energy doing that all work was absorbed as heat.

I hope it helps!

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3 years ago
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Komok [63]

Answer:

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Explanation:

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