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3 years ago

How is the combined gas law modified to form the ideal gas law?

1 answer:

4 0

The answer is A) each side of the equations is divided by the number of moles.
The combined gas law equation
P1V1/T1 = P2V2/T2
becomes
P1V1/n1T1 = P2V2/n2T2
with the addition of Avogadro's law relating volume and number of moles of a gas.This modification is when the number of moles of gas in a sample is allowed to change in addition to pressure, temperature and volume. This also means that pressure multiplied by the volume and divided by the product of the number of moles and temperature is a constant:
PV/nT = constant
which if written in the form PV = nRT is the ideal gas law equation where R is the gas constant.

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Shown below is a table with plants and animals with their adaptations.

zhenek [66]

Answer:

Desert

Explanation:

The adaptation shown by the given plants and animals shows that they will adapted to the desert biome.

It is so because, due to high temperature of desert some desert animals like camel have the storage of fat in humps or tails; some animals have large ears such as Jackrabbits, it helps to release body heat and adapt in high temperature; plants have thick water holding tissues to reduce water loss in heat and waxy coating that keeps the plants cooler and reduce moisture loss.

Hence, the correct answer is "Desert".

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3 years ago

The sun warming the surface of a rock is conduction convection radiation

Sindrei [870]

Radiation..................

7 0

3 years ago

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Calculate the solubility of hydrogen in water at an atmospheric pressure of 0.380 atm (a typical value at high altitude).

Pani-rosa [81]

The question is incomplete, here is the complete question:

Calculate the solubility of hydrogen in water at an atmospheric pressure of 0.380 atm (a typical value at high altitude).

Atmospheric Gas Mole Fraction kH mol/(L*atm)

$N_2$ $7.81\times 10^{-1}$ $6.70\times 10^{-4}$

$O_2$ $2.10\times 10^{-1}$ $1.30\times 10^{-3}$

Ar $9.34\times 10^{-3}$ $1.40\times 10^{-3}$

$CO_2$ $3.33\times 10^{-4}$ $3.50\times 10^{-2}$

$CH_4$ $2.00\times 10^{-6}$ $1.40\times 10^{-3}$

$H_2$ $5.00\times 10^{-7}$ $7.80\times 10^{-4}$

Answer: The solubility of hydrogen gas in water at given atmospheric pressure is $1.48\times 10^{-10}M$

Explanation:

To calculate the partial pressure of hydrogen gas, we use the equation given by Raoult's law, which is:

$p_{\text{hydrogen gas}}=p_T\times \chi_{\text{hydrogen gas}}$

where,

$p_A$ = partial pressure of hydrogen gas = ?

$p_T$ = total pressure = 0.380 atm

$\chi_A$ = mole fraction of hydrogen gas = $5.00\times 10^{-7}$

Putting values in above equation, we get:

$p_{\text{hydrogen gas}}=0.380\times 5.00\times 10^{-7}\\\\p_{\text{hydrogen gas}}=1.9\times 10^{-7}atm$

To calculate the molar solubility, we use the equation given by Henry's law, which is:

$C_{H_2}=K_H\times p_{H_2}$

where,

$K_H$ = Henry's constant = $7.80\times 10^{-4}mol/L.atm$

$p_{H_2}$ = partial pressure of hydrogen gas = $1.9\times 10^{-7}atm$

Putting values in above equation, we get:

$C_{H_2}=7.80\times 10^{-4}mol/L.atm\times 1.9\times 10^{-7}atm\\\\C_{CO_2}=1.48\times 10^{-10}M$

Hence, the solubility of hydrogen gas in water at given atmospheric pressure is $1.48\times 10^{-10}M$

4 0

3 years ago

Whats the number of moles of O2(g) needed to completely react with 8 moles of CO(g).

slava [35]

A mole of CO2 = 2 moles of O2
8 CO moles x 2 =

16 moles

7 0

3 years ago

What happens when you increase the temperature of a reaction?

aalyn [17]

D. More collisions occur and the time required for the reaction decreases
This happens because according to collision theory, when energy (in this case, thermal energy) is applied to particles, they move/vibrate more quickly.

7 0

3 years ago

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