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mel-nik [20]
4 years ago
8

A hardware store mixes paints in a ratio of three parts blue to five parts red to make two gallons of cabbage red . A ratio of s

even parts blue to one part red makes two gallons of eggplant purple . A gallon of cabbage red sells for ​$22 ​, and a gallon of eggplant purple sells for ​$26 . Find the cost of 1 quart of blue paint and the cost of 1 quart of red paint.
Mathematics
1 answer:
Anna71 [15]4 years ago
5 0
3b+5r=2 gallons of cabbage red
1r+7b=2gallons of egplant

1 gallon of cabbage sells for 22 (means 2 gallos is 44)
1 gallon of egplant is 26 (means 2 gallons is 52)

3b+5r=44
r+7b=52

r+7b=52
miinus 7b from both sides
r=52-7b
sub 52-7b for r in othe equestion
3b+5(52-7b)=44
3b+260-35b=44
-32b+260=44
minus 260 from both sides
-32b=-216
divide both sides by -32
b=6.75

r=52-7b
r=52-7(6.75)
r=52-47.25
r=4.75


3blue+5r=2gallons
5+3=8
8units=2gallons
 4units=1gallon
1unit=1quart

therefor

1 quart of blue paint is $6.75
1 quart of red paint is $4.75
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Joy recorded the distances she walked each day for five days. How far did she walk in 5 days? Line plot: 3 xs on 1/3 1 x on 1/2
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Answer:

2\frac{1}{6}\approx 2.167 units.

Step-by-step explanation:

We have been given that Joy recorded the distances she walked each day for five days.

To find the distance traveled be Joy in 5 days we will add the distances covered by Joy each day.

As there are 3 dots on 1/3, this means that Joy traveled 1/3 units on 3 days.

Since there is 1 dot on 1/2 and on dot on 2/3, so this means that Joy walked 1/2 units one day and 2/3 units another day.

Let us add all these distances.

\text{Total distance walked by Joy in 3 days}=3\times\frac{1}{3}+\frac{1}{2}+\frac{2}{3}

\text{Total distance walked by Joy in 3 days}=\frac{1*3}{3}+\frac{1}{2}+\frac{2}{3}

Let us have a common denominator.

\text{Total distance walked by Joy in 3 days}=\frac{3*2}{3*2}+\frac{1*3}{2*3}+\frac{2*2}{3*2}

\text{Total distance walked by Joy in 3 days}=\frac{6}{6}+\frac{3}{6}+\frac{4}{6}

\text{Total distance walked by Joy in 3 days}=\frac{6+3+4}{6}

\text{Total distance walked by Joy in 3 days}=\frac{13}{6}

\text{Total distance walked by Joy in 3 days}=2\frac{1}{6}

Therefore, Joy traveled 2\frac{1}{6}\approx 2.167 units in 5 days.

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