Height of the woman = 5 ft
Rate at which the woman is walking = 7.5 ft/sec
Let us assume the length of the shadow = s
Le us assume the <span>distance of the woman's feet from the base of the streetlight = x
</span>Then
s/5 = (s + x)/12
12s = 5s + 5x
7s = 5x
s = (5/7)x
Now let us differentiate with respect to t
ds/dt = (5/7)(dx/dt)
We already know that dx/dt = 7/2 ft/sec
Then
ds/dt = (5/7) * (7/2)
= (5/2)
= 2.5 ft/sec
From the above deduction, it can be easily concluded that the rate at which the tip of her shadow is moving is 2.5 ft/sec.
Answer:
-4/5
Step-by-step explanation:
To find the slope of the tangent to the equation at any point we must differentiate the equation.
x^3y+y^2-x^2=5
3x^2y+x^3y'+2yy'-2x=0
Gather terms with y' on one side and terms without on opposing side.
x^3y'+2yy'=2x-3x^2y
Factor left side
y'(x^3+2y)=2x-3x^2y
Divide both sides by (x^3+2y)
y'=(2x-3x^2y)/(x^3+2y)
y' is the slope any tangent to the given equation at point (x,y).
Plug in (2,1):
y'=(2(2)-3(2)^2(1))/((2)^3+2(1))
Simplify:
y'=(4-12)/(8+2)
y'=-8/10
y'=-4/5
<span>Step 1. Let x be the number and 1/x be its reciprocal.
Step 2. Then, since the sum of a number and its reciprocal is 25/12.
Step 3. Multiply 12x to both sides of the equation to get rid of the denominators.
Step 4. Subtract 25x to put the equation in quadratic form
</span>
Answer:
Step-by-step explanation:
Given
Required
Fill in the gap to produce the product of linear expressions
Split to 2
Factorize the first bracket
Represent the _ with X
Factorize the second bracket
To result in a linear expression, then the following condition must be satisfied;
Subtract b from both sides
Multiply both sides by 5
Substitute -15 for X in
The two linear expressions are 
and 
Their product will result in
<em>Hence, the constant is -15</em>
Answer:
y=3x+23 (lmk if you need me to explain)
Step-by-step explanation:
