Given:
The point, (4, -3)
The line,
To find an equation in slope-intercept form for the line that passes through (4,-3) and is parallel to the given line:
The slope of the line is,
Since the given line is parallel to the new line, so the slope will be same for the both.
Using the point-slope formula,
Substitute the point and slope we get,
Hence, the equation in slope-intercept form for the line is,
Answer:
min at (3, 0 )
Step-by-step explanation:
given a quadratic in standard form
y = ax² + bx + c ( a ≠ 0 )
then the x- coordinate of the vertex is
= -
y = (x - 3)² = x² - 6x + 9 ← in standard form
with a = 1 and b = - 6 , then
= -
= 3
substitute x = 3 into the equation for corresponding value of y
y = (3 - 3)² = 0² = 0
vertex = (3, 0 )
• if a > 0 then vertex is minimum
• if a < 0 then vertex is maximum
here a = 1 > 0 then (3, 0 ) is a minimum