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Levart [38]
3 years ago
6

Calculate the average speed of a gazelle that runs 140 meters in 5.0 seconds.

Mathematics
2 answers:
Grace [21]3 years ago
4 0
You would multiply to find the average meters/minute.
140 x 5.0 = 700.
But, if you're looking for average m/s you would divide.
140/5 = 28.
If you want meters/hour, you have to multiply the average meters/minute by 60.
140 x 5 x 60 = 4,200.

I'm not sure which one you're looking for but I hope something I wrote helps!
stiv31 [10]3 years ago
3 0

Answer:

Average speed(S) is given by:

S =\frac{D}{t}              ....[1]

where,

D is the total distance and t is the time.

As per the statement:

A gazelle that runs 140 meters in 5.0 seconds.

⇒D = 140 meters and t = 5 seconds

Substitute in [1] we have;

S =\frac{140}{5}

Simplify:

⇒S = 28 m/sec

Therefore, average speed of a gazelle is, 28 m/sec

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sammy [17]

Answer:

Mom === 10.25

Daughter === 3.25

Step-by-step explanation:

Let’s the mom age be 7+x and the daughters age be x. Put it in a linear equation 7+x=5(4+x).

open the bracket which will give you 7+x=20+5x.

collect like terms which will give you 5x-x=20–7 and you will get 4x=13 where x is 3.25 the mom is 10.25 and the daughters age is 3.25

6 0
2 years ago
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a bag of the same size small balls contains 6 blue balls 5 red balls 5 yellow balls and 4 green balls What is the probability of
valentinak56 [21]
You would start by finding the total amount of marbles, which in this case is 20.

Then find the total amount of blue AND green balls. 10.

Then put 10/20, simplify, and you have yourself 1/2.
6 0
3 years ago
Please help using the file below....
mrs_skeptik [129]
Third one is true and x is 22,000
hope this helps
5 0
3 years ago
ANSWER ASAP PLEASE & SHOW UR WORK!!!
Lina20 [59]

Answer:

x_1=\mathbf{i}\sqrt{6},\ x_2=-\mathbf{i}\sqrt{6},\ x_3=\sqrt{3},\ x_4=-\sqrt{3}

Step-by-step explanation:

<u>Biquadratic Equations</u>

Solve:

x^4 + 3x^2 - 18 = 0

The biquadratic equations are equations of degree 4 without the terms of degree 1 and 3.

Solving such equations requires to express the equation as a second-degree equation with x^2 as the variable.

Rewriting the equation:

(x^2)^2 + 3(x^2) - 18 = 0

The quadratic equation can be factored as:

(x^2+6)(x^2-3)=0

It leads to two equations:

x^2+6=0

x^2-3=0

The first equation has imaginary roots. Solving for x:

x^2=-6

x=\pm\sqrt{-6}

x_1=\mathbf{i}\sqrt{6}

x_2=-\mathbf{i}\sqrt{6}

Where

\mathbf{i}=\sqrt{-1}

The second equation has two real roots:

x^2-3=0

x^2=3

x=\pm\sqrt{3}

x_3=\sqrt{3}

x_4=-\sqrt{3}

The roots are:

\mathbf{x_1=\mathbf{i}\sqrt{6},\ x_2=-\mathbf{i}\sqrt{6},\ x_3=\sqrt{3},\ x_4=-\sqrt{3}}

3 0
3 years ago
A. Independent <br> B. Inconsistent <br> C. Equivalent <br> D. Consistent
tangare [24]

Answer:

B. Inconsistent (No solutions exist)

Step-by-step explanation:

The linear system that consists of parallel lines are <u><em>inconsistent</em></u><em>, </em>which means that no solutions exist.

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3 years ago
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