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Levart [38]
3 years ago
6

Calculate the average speed of a gazelle that runs 140 meters in 5.0 seconds.

Mathematics
2 answers:
Grace [21]3 years ago
4 0
You would multiply to find the average meters/minute.
140 x 5.0 = 700.
But, if you're looking for average m/s you would divide.
140/5 = 28.
If you want meters/hour, you have to multiply the average meters/minute by 60.
140 x 5 x 60 = 4,200.

I'm not sure which one you're looking for but I hope something I wrote helps!
stiv31 [10]3 years ago
3 0

Answer:

Average speed(S) is given by:

S =\frac{D}{t}              ....[1]

where,

D is the total distance and t is the time.

As per the statement:

A gazelle that runs 140 meters in 5.0 seconds.

⇒D = 140 meters and t = 5 seconds

Substitute in [1] we have;

S =\frac{140}{5}

Simplify:

⇒S = 28 m/sec

Therefore, average speed of a gazelle is, 28 m/sec

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The sound of a jet engine of a skyhawk jetfighter is 70000 times louder than the sound of a lawnmower if the lawnmower has the l
Amanda [17]

Answer: 6,160,000 db

Step-by-step explanation:

The sound of a jet engine is 70,000 times louder than that of a lawn mower.

Since we know the sound of a lawnmower, we can multiply that by 70,000 to find the sound of a jet engine:

= Sound of lawnmower * 70,000

= 88 * 70,000

= 6,160,000 db

8 0
3 years ago
The Bobcats had a win-loss record of 41-23 before their star player, Melissa, got injured. Melissa didn’t play in any more games
MrRissso [65]

Answer:

The win percentage decreased by 10%

Step-by-step explanation:

First you need to fin the total games played right before Melissa got Injured

41+23=64

Then you need to find the win percentage by making a fraction of wins over total games

wins/total games = 41/64 = 64%

Then you need to find the number of games played after Melissa got injured

54-41 = 13 wins

34-23 = 11 losses

13+11 = 24 total games played without Melissa

You find that win percentage similarly to the first time

wins/total games = 13/24 = 54%

Then you find the difference in the percentages and there you have it!!

64% - 54% = 10%

It decreased as well therefore the answer is...

It decreased by 10%

3 0
3 years ago
Gold in the form of solid cylinders will be molded into solid blocks. Each cylinder has a diameter of 6.19 cm and a height of 6
Taya2010 [7]
First, solve for the volume (V) of each cylinder by the equation,
                                     V = πd²h / 4
where d and h are diameter and height, respectively. Substituting the given values,
                                     V = π(6.19 cm)² x (6 cm) / 4 = 180.56 cm³
To determine the number of cylinders needed, divide the volume of the solid block by the volume of the cylinder,
                                       n = 360 cm³ / 180.56 cm³ = 1.99
Thus, approximately 2 cylinders are needed to mold one block of gold. 
5 0
3 years ago
Read 2 more answers
Find each missing measure.
Neporo4naja [7]

Answer:

m<A = 84

AC = 9

Step-by-step explanation:

We can find the measure of Angle A by using the sum of interior angles of a triangle theorem.

48+48+A=180

96+A=180

A=84

We can then use the isosceles triangle similarity theorem and reason that since this is an isosceles triangle and one of the side lengths (AB) is 9, the other (AC) would also be 9.

3 0
3 years ago
Read 2 more answers
Enter the coefficients of the fifth Taylor polynomial T5(x) for the function f(x) = x5−3x4+2x2+5x−2 based at b=1. T5(x)= + (x−1)
DENIUS [597]

Compute the necessary values/derivatives of f(x) at x=1:

f(1)=3

f'(1)=2

f''(1)=-12

f'''(1)=-12

f^{(4)}(1)=48

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Taylor's theorem then says we can "approximate" (in quotes because the Taylor polynomial for a polynomial is another, exact polynomial) f(x) at x=1 by

T_5(x)=\dfrac3{0!}+\dfrac2{1!}(x-1)-\dfrac{12}{2!}(x-1)^2-\dfrac{12}{3!}(x-1)^3+\dfrac{48}{4!}(x-1)^4+\dfrac{120}{5!}(x-1)^5

T_5(x)=3+2(x-1)-6(x-1)^2-2(x-1)^3+2(x-1)^4+(x-1)^5

###

Another way of doing this would be to solve for the coefficients a,b,c,d,e,g in

f(x)=a+b(x-1)+c(x-1)^2+d(x-1)^3+e(x-1)^4+g(x-1)^5

by expanding the right hand side and matching up terms with the same power of x.

5 0
3 years ago
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